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3 years ago

28 1/2% covert the percent to a decimal

Mathematics

1 answer:

rewona [7]3 years ago

8 0

Answer:

0.285

Step-by-step explanation:

To do this, divide 28 1/2% by 100%, obtaining:

28.5%

---------- = 0.285

100%

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What’s the distance between (4,-9) and (5,3)

laila [671]

Answer: Distance = √145

Concept:

Here, we need to know the concept of the distance formula.

The distance formula is the formula, which is used to find the distance between any two points.

If you are still confused, please refer to the attachment below for a clear version of the formula.

Solve:

Given information

(x₁, y₁) = (4, -9)

(x₂, y₂) = (5, 3)

Given formula

$Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute values into the formula

$Distance = \sqrt{(5-4)^2+(3+9)^2}$

Simplify values in the parentheses

$Distance = \sqrt{(1)^2+(12)^2}$

Simplify exponents

$Distance = \sqrt{1+144}$

Simplify by addition

$Distance = \sqrt{145}$

Hope this helps!! :)

Please let me know if you have any questions

7 0

2 years ago

Read 2 more answers

What is the following sale price for a phone charger with an original price of $1.99 after applying a discount of 20%

Zarrin [17]

Answer:

$1.59

Step-by-step explanation:

7 0

2 years ago

Evaluate using integration by parts

PolarNik [594]

Rather than carrying out IBP several times, let's establish a more general result. Let

$I(n)=\displaystyle\int x^ne^x\,\mathrm dx$

One round of IBP, setting

$u=x^n\implies\mathrm du=nx^{n-1}\,\mathrm dx$

$\mathrm dv=e^x\,\mathrm dx\implies v=e^x$

gives

$\displaystyle I(n)=x^ne^x-n\int x^{n-1}e^x\,\mathrm dx$

$I(n)=x^ne^x-nI(n-1)$

This is called a power-reduction formula. We could try solving for $I(n)$ explicitly, but no need. $n=5$ is small enough to just expand $I(5)$ as much as we need to.

$I(5)=x^5e^x-5I(4)$

$I(5)=x^5e^x-5(x^4e^x-4I(3))=(x-5)x^4e^x+20I(3)$

$I(5)=(x-5)x^4e^x+20(x^3e^x-3I(2))=(x^2-5x+20)x^3e^x-60I(2)$

$I(5)=(x^2-5x+20)x^3e^x-60(x^2e^x-2I(1))=(x^3-5x^2+20x-60)x^2e^x+120I(1)$

$I(5)=(x^3-5x^2+20x-60)x^2e^x+120(xe^x-I(0))$

Finally,

$I(0)=\displaystyle\int e^x\,\mathrm dx=e^x+C$

so we end up with

$I(5)=(x^4-5x^3+20x^2-60x+120)xe^x-120e^x+C$

$I(5)=(x^5-5x^4+20x^3-60x^2+120x-120)e^x+C$

and the antiderivative is

$\displaystyle\int2x^5e^x\,\mathrm dx=(2x^5-10x^4+40x^3-120x^2+240x-240)e^x+C$

8 0

2 years ago

A dog eats 7 cans of food in 3 days. At this rate, how many cans of food does the dog eat in 3 + d days?

Dafna1 [17]

The dog eats 7 cans plus d cans?
this any help?!!?

6 0

3 years ago

Read 2 more answers

(3z+1)(4z+2) simplify

Lorico [155]

You can FOIL (First, Outside, Inside, Last)

(3z+1)(4z+2)

First

(3z+1)(4z+2)

3z * 4z

$12z^{2}$

Outside

(3z+1)(4z+2)

3z * 2

Inside

(3z+1)(4z+2)

4z * 1

Last

(3z+1)(4z+2)

2*1

Combine all the products of FOIL together

$12z^{2}$ + 6z + 4z + 2

Combine like terms

$12z^{2}$ + 10z + 2

Hope this helped!

~Just a girl in love with Shawn Mendes

6 0

3 years ago