3 years ago

What is the minimum width of the square base?

Mathematics

1 answer:

riadik2000 [5.3K]3 years ago

4 0

4 I think I might be wrong so sorry if I am wrong

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If P = (5,4), find the image of P under the following rotation. 90° counterclockwise about the origin ([?], [ ])

ANTONII [103]

Answer: (-4,5)

Step-by-step explanation:

Rotating 90 deg. counterclockwise maps (x,y) onto (-y,x), so (5,4) maps onto (-4,5).

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2 years ago

What is the factored form of the expression? d^2 = 36d + 324

Veseljchak [2.6K]

Answer:

$(x-43.45)(x+7.45)=0$

Step-by-step explanation:

We have the quadratic equation $d^{2}=36d+324$ i.e. $d^{2}-36d-324=0$

As, the roots of the quadratic equation $ax^{2}+bx+c=0$ are given by $x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$ .

So, from the given equation, we have,

a = 1, b = -36 , c = -324.

Substituting the values in $x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$ , we get,

$x=\frac{36\pm \sqrt{(-36)^{2}-4\times 1\times (-324)}}{2\times 1}$

i.e. $x=\frac{36\pm \sqrt{1296+1296}}{2}$

i.e. $x=\frac{36\pm \sqrt{2592}}{2}$

i.e. $x=\frac{36\pm 50.9}{2}$

i.e. $x=\frac{36+50.9}{2}$ and $x=\frac{36-50.9}{2}$

i.e. $x=\frac{86.9}{2}$ and $x=\frac{-14.9}{2}$

i.e. x = 43.45 and x = -7.45

Thus, the roots of the equation are 43.45 and -7.45.

Hence, the factored form of the given expression will be $(x-43.45)(x+7.45)=0$

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Step-by-step explanation:

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3 years ago

Please help Simplify the following expression.

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Step-by-step explanation:

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2 years ago

Part A- solve for x Part B- solve for y Part C- find the perimeter (photo included)

lidiya [134]

Part A: x=3
Part B: y=3

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3 years ago