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elixir [45]
4 years ago
7

What is the minimum width of the square base?

Mathematics
1 answer:
riadik2000 [5.3K]4 years ago
4 0
4 I think I might be wrong so sorry if I am wrong
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Aubrey has a new art box in the shape of a rectangular prism. The box is 5 inches, by 8 inches, by 2 inches. How much volume is
VikaD [51]

volume of the rectangular prism = base area * height

base area = length * breadth

volume of the rectangular prism = length * breadth * height

volume of the rectangular prism = 5*8*2 = 80 inches ^3

volume of taken up by the eraser = 5.5 inches^3

volume that is not take-up by the eraser = 80-5.5 = 74.5 inches^3

7 0
3 years ago
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What is the cube of the difference of 40 and a number
tester [92]

Answer:

(40-y)^3

Step-by-step explanation:

Make the unknown y

(40-y)^3

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3 years ago
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A bird (B) is spotted flying 6,000 feet from a tower (). An observer (0) spots the top of tower (T) at a distance of 9,000 feet.
Kobotan [32]

Using relations in a right triangle, it is found that the angle of depression is of θ = 56.31º.

<h3>What are the relations in a right triangle?</h3>

The relations in a right triangle are given as follows:

  • The sine of an angle is given by the length of the opposite side to the angle divided by the length of the hypotenuse.
  • The cosine of an angle is given by the length of the adjacent side to the angle divided by the length of the hypotenuse.
  • The tangent of an angle is given by the length of the opposite side to the angle divided by the length of the adjacent side to the angle.

For this problem, we have that:

  • The opposite side to the angle of depression is the top of tower, at a height of 9000 feet.
  • The adjacent side to the angle is the distance to the bird, of 6000 feet.

Hence, considering θ as the depression angle, we have that:

tan(θ) = 9000/6000

tan(θ) = 1.5

θ = arctan(1.5)

θ = 56.31º.

More can be learned about relations in a right triangle at brainly.com/question/26396675

#SPJ1

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1 year ago
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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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