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scoundrel [369]
3 years ago
11

Matt's pool table is 3 feet wide and 9 feet long. Matt wants to replace the felt on the pool table. The felt costs $4.00 per squ

are foot. How much would it cost in total to replace the felt on the pool table?
Mathematics
1 answer:
RoseWind [281]3 years ago
4 0

Answer:

$108

Step-by-step explanation:

3X9= 27square foot. Then you multiply 27 by 4, which equals $108

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the diameter of a cylindrical construction pipe is 4 ft. if the pipe is 19 ft long, what s it’s volume?
choli [55]

Answer:

76\pi or 238.76 units^{3}

Step-by-step explanation:

The volume of a cylinder is V = \pi r^{2} h

Here the radius is  r = \frac{1}{2} d = \frac{1}{2}(4)=2

The height is given as 19 ft

Then plug in all the numbers into the equation

V = \pi (2^{2})(19) = 76\pi = 238.76 units^{3}

3 0
3 years ago
Julio tested the point (4, –2) to see whether it is a solution to this system of equations. –3x – 2y = –8, y = 2x – 5 His work i
kolezko [41]

if it is solution point (4, –2) must satisfy both equations
(1) –3x – 2y = –8-->-3*4-2*(-2)=-8
-12+4=-8 then-->-8=-8   ok
(2)  y = 2x – 5
-2=2*4-5=3---------->-2 is not 3

the point  (4, –2) is not solution of the system of equations
6 0
3 years ago
Read 2 more answers
Valerie bought a coat at a winter half-price sale. A sales tax of $6.24 was added to the sale price, bringing the cost of the co
egoroff_w [7]

Answer:

84.24 - 6.24 = p

Step-by-step explanation:

6 0
2 years ago
PLEASE HELP ME THIS.. I REALLY NEED<br> HELP
Colt1911 [192]

9514 1404 393

Answer:

  5 hours

Step-by-step explanation:

A quick way to look at this is to compare the difference in hourly charge to the difference in 0-hour charge.

The first day, the charge is $3 more than $12 per hour.

The second day, the charge is $12 less than $15 per hour.

The difference in 0-hour charges is 3 -(-12) = 15. The difference in per-hour charges is 15 -12 = 3. The ratio of these is ...

  $15/($3/h) = 5 h

The charges are the same after 5 hours.

__

If you write equations for the charges, they will look like ...

  y1 = 15 + 12(x -1)

  y2 = 3 + 15(x -1)

Equating these charges, we have ...

  15 +12(x -1) = 3 + 15(x -1)

  12x +3 = 15x -12 . . . . . . . . eliminate parentheses

  15 = 3x . . . . . . . . . . add 12-12x

  x = 15/3 = 5 . . . . . . divide by 3

You might notice that the math here is very similar to that described in words, above.

The charges are the same after 5 hours.

6 0
3 years ago
A. Find 33 and a third % of 879
Anvisha [2.4K]

Answer:

Step-by-step explanation:

4 0
3 years ago
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