This is a rather famous probability problem.
The easiest way to solve this is to calculate the probability that you WON'T roll a "double 6" (or a twelve) each time you roll the dice. There are 36 ways in which dice rols can appear and only one is a twelve. So, for one roll, the probability that you will NOT get a twelve is (35/36)^n where 35/36 is about .97222222 and n would equal 1 for the first trial. So for your first roll the odds that you WON'T get a 12 is .97222222.
For the second roll we calculate (35/36) to the second power or (35/36)^2 which equals about .945216.
When we get to the 24th roll we calculate (.97222222)^24 which equals 0.508596.
For the 25th roll, we calculate (.97222222)^25 which equals 0.494468. For the first time we have reached a probability which is lower than 50 per cent. That is to say, after 25 rolls, we have reached a point in which the probability is less than 50 per cent that we will NOT roll a twelve.
To phrase this more clearly, after 25 rolls we reach a point where the probability is greater then 50 per cent that you will roll a 12 at least once.
Please go to this page 1728.com/puzzle3.htm and look at puzzle 48. (The last puzzle on the page). An intersting story associated with this probability problem is that in 1952, a gambler named Fat the Butch bet someone $1,000 that he could roll a 12 after 21 throws. (He miscalculated the odds [as we know you need 25 throws] and after several HOURS, he lost $49,000!!!)
Please go that page and it has a link to the Fat the Butch story.
Answer:
28 baskets
Step-by-step explanation:
Total Shots = 100
Backboard and miss = 2/5 of total
That is:
Rim and miss = 32% of total
That is:
32% = 32/100 = 0.32
0.32 * 100 = 32 shots
So, miss = 40 + 32 = 72
The rest, she makes, so left:
100 - 72 = 28 shots
Alicia makes 28 baskets (from 100)
Answer:
tan(x-y) = -16/63
Step-by-step explanation
Tan(x-y) if cscx=13/5 and coty=4/3
Given
coty = 4
1/tany = 4/3
Cross multiply
tan y = 3/4
Also since cscx = 13/5
1/sinx = 13/5
sinx = 5/13
Since sinx = opp/hyp
opp = 5
hyp = 13
Get the adjacent
hyp² = opp²+adj²
13² = 5²+adj²
adj² = 13² - 5²
adj² = 169 - 25
adj² = 144
adj = 12
cosx = adj/hyp
cosx = 12/13
tanx = sinx/cosx
tanx = (5/13)/(12/13)
tanx = 5/13 * 13/12
tan x = 5/12
tan(x-y) = tanx - tany/1+tanxtany
tan(x-y) = (5/12 - 3/4)/1+(5/12)(3/4)
tan(x-y) = (5-9/12)/1+5/16
tan(x-y) = -4/12/(21/16)
tan(x-y) = -1/3 * 16/21
tan(x-y) = -16/63
Ummmmmmm yeah..what is this
Answer:
Option A.
Step-by-step explanation:
Properties of the similarity of two polygons,
1). All angles of one polygon will be equal to the angles of the other polygon.
2). Their corresponding sides will be in the same ratio.
If the measures of corresponding angles of KLMN and ABCD are equal, but the lengths of the corresponding sides of ABCD are half those of KLMN,
Then the polygons ABCD and KLMN will be similar.
Option A will be the answer.
