Question

Item 16 A rectangular garden is 6 feet long and 4 feet wide. A second rectangular garden has dimensions that are double the dimensions of the first garden. What is the percent of change in perimeter from the first garden to the second garden?

Answer 1

P=2(L+W)
first one
P=2(6+4)
P=2(10)=20

doubled

12 and 8
P=2(12+8)
P=2(20)
P=40

the change is i20
percent change=change/original
change/original=20/20=1=100%


100% change