The first step is to combine like terms. So u would do 2-6. You then get -4 then u just bring everything else down. So now u should have this :

8x -4 = 4x + 8 + 3x

Now you do the same thing to the other side. U combine like terms which in this case are 4x and 3x. So u just do 4+3 which is 7 so now u have 7x. So now ur equation would be:

8x -4 = 7x +8

Now u do the inverse of 7 which would be -7 and u do that on both sides. So it would look like this :

8x -4 = 7x + 8
-7x. -7x

So now 7 and -7 cancel each other other and 8 -7 is 1 so now u have one x. So ur equation would now look like this:

1x -4 = 8

Now u do the inverse of negative 4 which is +4. So you would add 4 on both sides on both sides. Like shown:

1x -4 = 8
+4 +4

So u just add 8 + 4 which is 12. Now since anything times 1 is itself ur answer will be X=12

Hope this helped

4 0

3 years ago

-3 - 6(4x+6) = -11 What is x?

Thepotemich [5.8K]

Answer:

x=-7/6

alternate form-x=-1 1/6

3 0

3 years ago

Find f. (Use C for the constant of the first antiderivative and D for the constant of the second antiderivative.)

sashaice [31]

Answer:

$f(x) = x^3 -sinx +Cx+D$

Step-by-step explanation:

Given that:

$f ''(x)= 6x +sinx$

We are given the 2nd derivative of a function f(x) and we need to find f(x) from that.

We will have to integrate it twice to find the value of f(x).

Let us have a look at the basic formula of integration that we will use in the solution:

$1.\ \int {(a\pm b)} \, dx =\int {a} \, dx + \int {b} \, dx \\2.\ \int {x^n} \, dx = \dfrac{x^{n+1}}{n+1}+C\\3.\ \int {sinx} \, dx = -cosx+C\\4.\ \int {cosx} \, dx = sinx+C$

$\int\ {f''(x)} \, dx =\int\ {(6x +sinx)} \, dx \\\Rightarrow \int\ {6x} \, dx + \int\ {sinx} \, dx \\\\\Rightarrow 6\dfrac{x^2}{2} -cosx +C\\\Rightarrow 3{x^2} -cosx +C\\\Rightarrow f'(x)=3{x^2} -cosx +C\\$

Now, integrating it again to find f(x):

$f(x) =\int {f'(x)} \, dx =\int{(3{x^2} -cosx +C)} \, dx \\\Rightarrow \int{3{x^2}} \, dx -\int{cosx} \, dx +\int{C} \, dx\\\Rightarrow 3\times \dfrac{x^3}{3} -sinx +Cx+D\\\Rightarrow x^3 -sinx +Cx+D\\\\\therefore f(x) = x^3 -sinx +Cx+D$

5 0

4 years ago