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nalin [4]
3 years ago
8

What equation is the result of solving 7+4x=3y for x

Mathematics
2 answers:
ehidna [41]3 years ago
8 0

Answer:

x=3y/4 - 7/4

Step-by-step explanation:

lara31 [8.8K]3 years ago
7 0

Answer:

x = \frac{3y-7}{4}

Step-by-step explanation:

Given

7 + 4x = 3y ( subtract 7 from both sides )

4x = 3y - 7 ( divide both sides by 4 )

x = \frac{3y-7}{4}

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Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different
N76 [4]

Answer:

(a)  As time increases, the amount of water in the pool increases.

     11 gallons per minute

(b)  65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

We are told that Ann adds water at a constant rate.  Therefore, this can be modeled as a linear function.  

The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

Choose 2 ordered pairs from the table:

\textsf{let}\:(x_1,y_1)=(8, 153)

\textsf{let}\:(x_2,y_2)=(12,197)

Input these into the slope formula:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11

Therefore, the rate at which the water in the pool is increasing is:

<u>11 gallons per minute</u>

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

y-y_1=m(x-x_1)

\implies y-153=11(x-8)

\implies y-153=11x-88

\implies y=11x-88+153

\implies y=11x+65

When Ann had added no water, x = 0.  Therefore,

y=11(0)+65

y=65

So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.

3 0
2 years ago
Read 2 more answers
-5.5x+0.77=1.48 whats x
Nesterboy [21]

Answer:

X= -0.1290 (bar line on top of the 90)

Hope this helps!

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Radical expression of 4d 3/8
DanielleElmas [232]

Answer:

\boxed{4 \sqrt[8]{ {d}^{3} } }

Step-by-step explanation:

=  > 4 {d}^{ \frac{3}{8} }   \\  \\ =   > 4({d}^{3 \times  \frac{1}{8} }) \\  \\  =  > 4( {d}^{3}  \times   {d}^{ \frac{1}{8} } ) \\  \\  =  > 4( {d}^{3}  \times  \sqrt[8]{d} ) \\  \\  =  > 4  \sqrt[8]{ {d}^{3} }

8 0
2 years ago
Oil leaked from a tank at a rate of r(t) liters per hour. the rate decreased as time passed, and values of the rate at two hour
Galina-37 [17]
The given data is
t, h:            0     2     4     6     8   10
r(t), L/h:   8.6  7.9  6.8  6.4  5.7  5.3

The lower and upper estimates for the total amount that leaked may be computed as the Left and Right Riemann sums.

The shape of the graph of r versus will determine which of the two sums yields an upper or lower sum.
The plot of the graph is shown below.

The Left Riemann sum is
Sl = 2*(8.6+7.9+6.8+6.4+5.7) = 70.8 L

The Right Riemann sum is
Sr = 2*(7.9+6.8+6.4+5.7+5.3) = 64.2 L

Answer:
The lower estimate for oil leakage is 64.2 L
The upper estimate for oil leakage is 70.8 L

4 0
3 years ago
Read 2 more answers
PLEASE HELP ME IM BAD AT GEO! URGENT
cupoosta [38]

Answer:

SSS

Step-by-step explanation:

Given that the sides are equal and no angles are given

6 0
3 years ago
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