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Inga [223]
3 years ago
15

-3 - 6(4x+6) = -11 What is x?

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
3 0

Answer:

x=-7/6

alternate form-x=-1 1/6

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slamgirl [31]
<span>6b^3 (2a+7b)

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<span><span>(<span>6b^3</span>)</span><span>(<span>2a+7b</span><span>)

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<span><span><span>=(<span>6b^3</span>)</span><span>(2a)</span></span>+<span><span>(<span>6b^3</span>)</span><span>(7b)

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<span><span>=12ab^3</span>+<span>42<span>b^4]



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<span><span><span>12a</span><span>b^3</span></span>+<span>42<span>b^4</span></span></span>    
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3 years ago
What is the mode?<br> 8 8 6 8 6
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Answer:8

Step-by-step explanation:

It appears the most in the set of data

3 0
3 years ago
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Graph g(x) = -3(x + 2)2 + 2. Compare the graph to the graph of f(x) = x2. Give me five points that you use to graph g(x). Then d
PolarNik [594]
The answer would be -20 because you add and subtract your numbers to get 20
4 0
3 years ago
The members of a high school band asked a number of students whether they would like blue, gold, or both for the uniforms for th
MaRussiya [10]

The values of a and b are a = 33% and b = 43% ⇒ last answer

Step-by-step explanation:

The venn-diagram contains:

  • A circle labeled blue 32
  • A circle labeled gold 25
  • The two circles are overlap with label 12 on the overlap

The table:

→ Band  :  blue  :  N.b  : total

→ gold   :  16%   :  a      :  49%

→ N.g     :  b       :  8%   :  51%

→ Total  :  59%  :  41%  :  100%

We need to find the values of a and b

From the table

16% represents the percentage of blue and gold uniforms (2nd row with 2nd column)

From venn-diagram

The common part of blue and gold label with 12 (overlap of two circles)

∴ 16% of the total number of students = 12

∵ 16% × x = 12

∴ \frac{16}{100} × x = 12

∴ 0.16 x = 12

- Divide both sides by 0.16

∴ x = 75

∵ x represents the total number of students

∴ The total number of students were asked is 75

From the table

b represents the percentage of blue but not gold uniforms (3rd row and 2nd column)

From venn-diagram

The part that has blue and not gold labeled with 32 (the part of the blue circle not in the gold circle)

∴ 32 of the total number of students like the blue but not gold

- Divide 32 by the total 75 , then multiply the quotient by 100%

   to find the percentage of blue but not gold

∴ b = \frac{32}{75} × 100% = 42.6666%

∴ b ≅ 43%

From the table

a represents the percentage of gold nut not blue uniforms (2nd row and 3rd column)

From venn-diagram

The part that has gold and not blue labeled with 25 (the part of the gold circle not in the blue circle)

∴ 25 of the total number of students like the gold but not blue

- Divide 25 by the total 75 , then multiply the quotient by 100%

   to find the percentage of gold but not blue

∴ a = \frac{25}{75} × 100% = 33.3333%

∴ a ≅ 33%

The values of a and b are a = 33% and b = 43%

To check your answer complete the table you will find the total of it is 100% ( for the columns 16% + 43% = 59% , 33% + 8% = 41% , then 59% + 41% = 100%, for the rows 16% + 33% = 49% , 43% + 8% = 51% , then 49% + 51% = 100%)

Learn more:

You can learn more about the probability in brainly.com/question/3756853

#LearnwithBrainly

4 0
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A stadium has 47000 seats seats sell for $35 in section a $30 in section B and 25 in section c the number of seats in section A
Rainbow [258]

Answer: a section holds 11,750 seats

$1,483,500 from one sold out event

47,000 seats in total, 3 sections (A = B + C)

A = B*2, C*2

47,000 / 4 = 11,750

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