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Katen [24]
2 years ago
12

68,435,190 in word form

Mathematics
2 answers:
Nat2105 [25]2 years ago
8 0

sixty-eight million four hundred thirty five thousand 1 hundred ninety

Orlov [11]2 years ago
5 0

sixty eight million, four hundred thirty five thousand, one hundred and nienty

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If Li goes on 32 out of 100 rides at an amusement park, what percentage of
lyudmila [28]

Answer:

A. 68%

Step-by-step explanation:

68 + 32 = 100, therefore the answer is 68%.

5 0
3 years ago
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Ms.Tao flies roundtrip twice yearly between Jacksonville and Los Angeles on business the distance between the two cites is 2,150
vlabodo [156]
2,150 estimated would be 2,000. Since she flies there and back multiply 2,000 by 2. Since she flies it twice multiply 4,000 by 2. Estimated: 8,000 miles. To find the exact miles Do the same thing but with 2,150: 2,150 times 2 = 4,300. 4,300 times 2 = 8,600. She flies exactly 8,600 miles per year :)
8 0
2 years ago
Jen uses 8.6 gallons of gasoline to drive 164.7 miles. Which is the best estimate for thenumber of miles per gallon of gasoline
zimovet [89]

Answer:

C

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164.7/8.6 = 19.15

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4 0
3 years ago
891 is 99% of what amount?
vaieri [72.5K]

Answer:

900

Step-by-step explanation:

Hope this helps!

6 0
3 years ago
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Solve x^3-7x^2+7x+15​
ruslelena [56]

Step-by-step explanation:

\underline{\textsf{Given:}}

Given:

\mathsf{Polynomial\;is\;x^3+7x^2+7x-15}Polynomialisx

3

+7x

2

+7x−15

\underline{\textsf{To find:}}

To find:

\mathsf{Factors\;of\;x^3+7x^2+7x-15}Factorsofx

3

+7x

2

+7x−15

\underline{\textsf{Solution:}}

Solution:

\textsf{Factor theorem:}Factor theorem:

\boxed{\mathsf{(x-a)\;is\;a\;factor\;P(x)\;\iff\;P(a)=0}}

(x−a)isafactorP(x)⟺P(a)=0

\mathsf{Let\;P(x)=x^3+7x^2+7x-15}LetP(x)=x

3

+7x

2

+7x−15

\mathsf{Sum\;of\;the\;coefficients=1+7+7-15=0}Sumofthecoefficients=1+7+7−15=0

\therefore\mathsf{(x-1)\;is\;a\;factor\;of\;P(x)}∴(x−1)isafactorofP(x)

\mathsf{When\;x=-3}Whenx=−3

\mathsf{P(-3)=(-3)^3+7(-3)^2+7(-3)-15}P(−3)=(−3)

3

+7(−3)

2

+7(−3)−15

\mathsf{P(-3)=-27+63-21-15}P(−3)=−27+63−21−15

\mathsf{P(-3)=63-63}P(−3)=63−63

\mathsf{P(-3)=0}P(−3)=0

\therefore\mathsf{(x+3)\;is\;a\;factor}∴(x+3)isafactor

\mathsf{When\;x=-5}Whenx=−5

\mathsf{P(-5)=(-5)^3+7(-5)^2+7(-5)-15}P(−5)=(−5)

3

+7(−5)

2

+7(−5)−15

\mathsf{P(-5)=-125+175-35-15}P(−5)=−125+175−35−15

\mathsf{P(-5)=175-175}P(−5)=175−175

\mathsf{P(-5)=0}P(−5)=0

\therefore\mathsf{(x+5)\;is\;a\;factor}∴(x+5)isafactor

\underline{\textsf{Answer:}}

Answer:

\mathsf{x^3+7x^2+7x-15=(x-1)(x+3)(x+5)}x

3

+7x

2

+7x−15=(x−1)(x+3)(x+5)

\underline{\textsf{Find more:}}

Find more:

6 0
3 years ago
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