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2 years ago

HELP

Mathematics

1 answer:

aleksklad [387]2 years ago

4 0

f is a function defined by

{(-3, 1), (-2, 2), (-1, -3), (0, -1), (1, 3), (2, -2), (3, 0)}

so f (1) = 3. Then

h (g (i (j (f (1))))) = h (g (i (j (3))))

j is defined by

{(-3, 0), (-2, 1), (-1, 2), (0, -1), (1, -2), (2, 3), (3, -3)}

so j (3) = -3, and

h (g (i (j (f (1))))) = h (g (i (-3)))

And so on. Next you have i (-3) = 2, then g (2) = 0, and finally, h (0) = 0, so your answer is correct.

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Answer:

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Why is (x-3) NOT a factor of x3+2x2-5x-6

ivolga24 [154]

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Step-by-step explanation:

Given expression is:

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In order for x-3 to be a factor of expression, we have to put x-3 = 0 => x=3 in expression.

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