10000 times the value of the other one
Answer:
The cost for 1 chair is $2.75 and the cost for 1 table is $8.75
Step-by-step explanation:
Use the elimination method of linear equations to find your answer.
Our equations for this problem are:
3c+5t=52 and 9c+7t=86
1. Multiply the entire first equation by -3.
-3(3c+5t=52)
2. Simplify the equation from above:
-9c-15t=-156
3. Stack the two equations on top of each other and add/subtract:
-9c-15t=-156
9c+7t=86
4. You should be left with -8t=-70. Simplify this to find the value of t:
t=8.75
5. Plug the value of t into any of the original equations and solve for c.
3c+5(8.75)=52
6. Simplify the equation above:
3c+43.75=52
7. Subtract 43.75 from both sides of the equation:
3c=8.25
8. Divide both sides by 3 to get your c value:
c=2.75
Check the angle. If it they are less than 90°<span> , so they will result in acute angles. </span>
Answer:
15u + 141 = 420
Step-by-step explanation:
So basically we are modelling how much the coach is spending. Each player is given a uniform and a basketball
We can use 'u' as the cost of a single uniform
We can use 'b' as the cost of a single basketball
Since there is 15 players we must give a ball and uniform to each so
15u + 15b = 420
The problem gives us the cost of each basketball: 9.40
so now 15u + 15(9.4) = 420
15u + 141 = 420