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WARRIOR [948]
3 years ago
7

A rectangle has an area of 8x2 - 2x - 45. The length of the

Mathematics
1 answer:
Savatey [412]3 years ago
5 0

Answer:

Width = W = 2x-5

Step-by-step explanation:

Given Data:

Length of rectangle = L = 4x + 9 ------->(Equation 1)

Area of rectangle = A = 8x^{2} - 2x -45 square inches ------->(Equation 2)

To find out:  

Width of rectangle = W = ?  

Formula:  

Area = A = L×W

Width = W = \frac{A}{L}

Solution:  

Width = W = \frac{A}{L}

Width = W = \frac{8x^{2} - 2x - 45 }{4x+9}

For complete division check the attached image.

Width = W = 2x-5 inches

 

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To solve, simply do this:

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Answer:

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Step-by-step explanation:

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we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power:  3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

x^{2}+6x+9-9-5=0

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lets apply square root on both sides of the equation:

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