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3 years ago

1/2,2/5,3/5,3/7 from least to greatest

Mathematics

2 answers:

maw [93]3 years ago

7 0

The answer above is correct

soldier1979 [14.2K]3 years ago

6 0

your answer would be
2/5, 3/7, 3/5, 1/2

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2 years ago

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3 years ago

Let f(x) = e ^3x/5x − 2. Find f'(0).

Romashka-Z-Leto [24]

Answer:

Step-by-step explanation:

Our friend asking what the actual function is has a point. I completed this under the assumption that what we have is:

$f(x)=\frac{e^{3x}}{5x-2}$ and used the quotient rule to find the derivative, as follows:

$f'(x)=\frac{e^{3x}(5)-[(5x-2)(3e^{3x})]}{(5x-2)^2}$ and simplifying a bit:

$f'(x)=\frac{5e^{3x}-[15xe^{3x}-6e^{3x}]}{(5x-2)^2}$ and a bit more to:

$f'(x)=\frac{5e^{3x}-15xe^{3x}+6e^{3x}}{(5x-2)^2}$ and combining like terms:

$f'(x)=\frac{11e^{3x}-15xe^{3x}}{(5x-2)^2}$ and factor out the GFC in the numerator to get:

$f'(x)=\frac{e^{3x}(11-15x)}{(5x-2)^2}$ That's the derivative simplified. If we want f'(0), we sub in 0's for the x's in there and get the value of the derivative at x = 0:

$f'(0)=\frac{e^0(11-15(0))}{(5(0)-2)^2}$ which simplifies to

$f'(0)=\frac{11}{4}$ which translates to

The slope of the function is 11/4 at the point (0, -1/2)

4 0

2 years ago

E(5,3) and F (2,-1) are two vertices of a square EFGH and H is in the x-axis .Find the coordinates of H and G. Please need answe

timurjin [86]

Answer:

coordinates of H = (1, 0)

Coordinates of G = ( - 3.6, -2) or (5.6, -2)

Step-by-step explanation:

E(5,3) and F (2,-1) are two vertices of a square EFGH and H is in the x-axis.

Let the coordinates of H is (x, 0) and G is (a, b).

The length of side EF is

$EF = \sqrt{(5 -2)^2 + (3 +1)^2} = 5$

So,

$EH = \sqrt{(5 -x)^2 + (3 -0)^2} = 5\\\\(5 -x)^2+ 9 = 25\\\\5 - x = 4\\\\x = 1$

And

$GH = \sqrt{(a -x)^2+ b^2} = 5\\\\(a -1)^2+ b^2 = 25\\\\a^2 + b^2 + 1 - 2 a = 25\\\\a^2 + b^2 - 2a = 24 .... (1)$

Now

$FG = \sqrt{(a -2)^2+ (b +1)^2} = 5\\\\(a -2)^2+ (b+1)^2 = 25\\\\a^2 + b^2 + 2b - 2 a = 20\\ ..... (2)$

Solving (1) and (2)

b = - 2 ,

$a = \frac{2 \pm\sqrt{4 + 80}}{2}\\\\a = \frac{2 \pm 9.2}{2}\\\\a = - 3.6, 5.6$

3 0

3 years ago