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3 years ago

14

In a completely randomized design involving three treatments, the following information is provided:Treatment 1Treatment 2Treatm

ent 3Sample Size5105Sample Mean489The overall mean for all the treatments is _______.

1 answer:

Aliun [14]3 years ago

6 0

Answer:

7.25

Step-by-step explanation:

Given :

___________ Sample size __ sample mean

Treatment 1 ____ 5 _______ 4

Treatment 2 ____ 10 ______ 8

Treatment 3 ____ 5 _______ 9

Sample size = (5 + 10 + 5). = 20

Overall mean = ((5*4). + (10*8) + (5*9)) / 20

Overall mean = (20 + 80 + 45) / 20

= 145 / 20

= 7.25

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Stats. can someone help?

artcher [175]

Answer:

you should try picto math it very helpful!

Step-by-step explanation:

5 0

3 years ago

The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room

Alexandra [31]

Answer:

$\bar x = 260.1615$

$\sigma = 70.69$

The confidence interval of standard deviation is: $53.76$ to $103.25$

Step-by-step explanation:

Given

$n =20$

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}$

$\bar x = \frac{5203.23}{20}$

$\bar x = 260.1615$

$\bar x = 260.16$

Solving (b): The standard deviation

This is calculated as:

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}$

$\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}$ $\sigma = \sqrt{\frac{94938.80}{19}}$

$\sigma = \sqrt{4996.78}$

$\sigma = 70.69$ --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

$c =0.95$

So:

$\alpha = 1 -c$

$\alpha = 1 -0.95$

$\alpha = 0.05$

Calculate the degree of freedom (df)

$df = n -1$

$df = 20 -1$

$df = 19$

Determine the critical value at row $df = 19$ and columns $\frac{\alpha}{2}$ and $1 -\frac{\alpha}{2}$

So, we have:

$X^2_{0.025} = 32.852$ ---- at $\frac{\alpha}{2}$

$X^2_{0.975} = 8.907$ --- at $1 -\frac{\alpha}{2}$

So, the confidence interval of the standard deviation is:

$\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} }$ to $\sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }$

$70.69 * \sqrt{\frac{20 - 1}{32.852}$ to $70.69 * \sqrt{\frac{20 - 1}{8.907}$

$70.69 * \sqrt{\frac{19}{32.852}$ to $70.69 * \sqrt{\frac{19}{8.907}$

$53.76$ to $103.25$

8 0

3 years ago

If x varies directly with y and x = 2.5 when y = 10, funny x when y = 16.

amid [387]

Answer:

Should be 4.0(Not sure tho. my thought process is complicated but to me it makes sense)

Step-by-step explanation:

If y=10 and x =2.5, if y were to = 20, then x would equal 5. so you take that ratio, and say 6 is 3/5's the way to 10, so you also divide 2.5 by 3/5

you get 1.5, you add that to x already and you get 4.0

so if y=16, x should =4.0

3 0

3 years ago

A rectangle has a width of 2cm and a perimeter of 25cm. Find the length and the area .

Gwar [14]

2w + 2l = 25

2 * 2 + 2l = 25

<em><u>Simplfiy.</u></em>

4 + 2l = 25

<em><u>Subtract 4 from both sides.</u></em>

2l = 21

<em><u>Divide both sides by 2.</u></em>

l = 10.5

Now that we have the value of l, we can find the area.

A = lw

A = 10.5 * 2

A = 21.

The length is 10.5cm.

The area of the rectangle is 21cm^2

5 0

3 years ago

Write the slope intercept form of an equation with a slope of 5 and y-intercept of -4

Delvig [45]

Answer:

y = 5x - 4

Step-by-step explanation:

5 is the slope so it goes in front of the x and -4 is the y Intercept so it goes last.

5 0

3 years ago