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3 years ago

S/t=t/v, solve for s

Mathematics

1 answer:

Gwar [14]3 years ago

3 0

Answer:

s = t²/v

Step-by-step explanation:

The variable s is divided by t. To undo that division, multiply the equation by t.

s = t²/v

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I beg of you to help me I need to be able to graduate

Ne4ueva [31]

Answer:

this i not high school work

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2 years ago

One number is six times another number. Their difference is 35. What are the two numbers?

konstantin123 [22]

x - y = 35
x = 6y
Plug 6y in for x in the first equation.
6y - y = 35
5y = 35
Divide both sides by 5
y = 7
x = 6y
x = 6(7) = 42
42 and 7
Letter C
Since we had the answers we could have just tried the answers but you will not always have multiple choice so this is the method for solving.

4 0

3 years ago

Read 2 more answers

Find the solution set to this inequality: 2x − 3 > _ <br> 2x − 5 <br> 2

Molodets [167]

Answer:

<h2>WOW!!What an amazing question</h2>

3 0

2 years ago

HELLOOOO HELP PLEASE

MA_775_DIABLO [31]

Answer:

$2*log(x)+log(y)$

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

<em>Logarithm of a power</em>:

$log_ba^c=c*log_ba$

So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: $log_ba=x\implies b^x=a$

Now if we raise both sides to the power of c, we get the following equation: $(b^x)^c=a^c$

Using the exponential identity: $(x^a)^c=x^{a*c}$

We get the equation: $b^{xc}=a^c$

If we convert this back into logarithmic form we get: $log_ba^c=x*c$

Since x was the basic logarithm we started with, we substitute it back in, to get the equation: $log_ba^c=c*log_ba$

Now the second logarithmic property you need to know is

<em>The Logarithm of a Product</em>:

$log_b{ac}=log_ba+log_bc$

Now for a quick proof, let's just say: $x=log_ba\text{ and }y=log_bc$

Now rewriting them both in exponential form, we get the equations:

$b^x=a\\b^y=c$

We can multiply a * c, and since b^x = a, and b^y = c, we can substitute that in for a * c, to get the following equation:

$b^x*b^y=a*c$

Using the exponential identity: $x^{a}*x^b=x^{a+b}$ , we can rewrite the equation as:

$b^{x+y}=ac$

taking the logarithm of both sides, we get:

$log_bac=x+y$

Since x and y are just the logarithms we started with, we can substitute them back in to get: $log_bac=log_ba+log_bc$

Now let's use these identities to rewrite the equation you gave

$log(x^2y)$

As you can see, this is a log of products, so we can separate it into two logarithms (with the same base)

$log(x^2)+log(y)$

Now using the logarithm of a power to rewrite the log(x^2) we get:

$2*log(x)+log(y)$

3 0

1 year ago

Eric and Mark were at a ball game and visited the concession stand. They each got a hamburger, and Mark got lemonade and some co

EastWind [94]

So here is the answer. Given that both Eric and Mark got a hamburger which is $4 each. Mark got a lemonade and some cotton candy which costs $5.
So this gives them a total of $4, $4, $5, $?(lemonade). Partial sum is $13 without the lemonade. Since Eric got a $2, the total bill was deducted with $2 and the rest of the amount is $14.50. Therefore, the total bill would have been $16.50. So $16.50 minus $13 (partial sum) is $3.50. So the lemonade costs $3.50. Hope this helps.

3 0

3 years ago