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True [87]
3 years ago
10

Is 12 fl oz equal to 355 ml

Mathematics
2 answers:
Karolina [17]3 years ago
7 0
Yes because I think 29 mL is about 1 fl oz so 29*12 is about 355.
iragen [17]3 years ago
4 0
1 fl oz = 30ml
So take 30*12 = 360ml
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Which ordered pair is a solution of the equation?<br> y = -6x+1
alekssr [168]

Answer:

2,-11

Step-by-step explanation:

create an x/y table and plug in #s for ordered pairs

-6x + 1 = y [plug in 2 for x]

-12 + 1 = -11 [ordered pair is 2, -11]

7 0
3 years ago
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I need help please help me im struggling please show WORK and tell me how to do it NO links please.
stellarik [79]

Answer:

- 7y +3 =-25

-7y=-25—3

-7y=-28

-7y÷-7= -28÷-7

y=4

Step-by-step explanation:

Take +3 to the side so that your variable and a constant is on their own sides. When a number goes over the equals sign the sign changes at becomes the inverse that's why l said - 3. You now calculate - 25—3 equals 28 then divide by 7 to find y and your y is 4.

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3 years ago
The height of a plant in mm is 7. It doubles each week. Select all expressions that represent the
MaRussiya [10]

Answer:

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4 0
2 years ago
An important tool in archeological research is radiocarbon dating, developed by the American chemist Willard F. Libby.3 This is
Radda [10]

Answer:

Q(t) = Q_o*e^(-0.000120968*t)

Step-by-step explanation:

Given:

- The ODE of the life of Carbon-14:

                                       Q' = -r*Q

- The initial conditions Q(0) = Q_o

- Carbon isotope reaches its half life in t = 5730 yrs

Find:

The expression for Q(t).

Solution:

- Assuming Q(t) satisfies:

                                       Q' = -r*Q

- Separate variables:

                                      dQ / Q = -r .dt

- Integrate both sides:

                                       Ln(Q) = -r*t + C

- Make the relation for Q:

                                       Q = C*e^(-r*t)

- Using initial conditions given:

                                       Q(0) = Q_o

                                       Q_o = C*e^(-r*0)

                                      C = Q_o    

- The relation is:

                                       Q(t) = Q_o*e^(-r*t)

- We are also given that the half life of carbon is t = 5730 years:

                                       Q_o / 2 = Q_o*e^(-5730*r)

                                        -Ln(0.5) = 5730*r

                                        r = -Ln(0.5)/5730

                                        r = 0.000120968          

- Hence, our expression for Q(t) would be:

                                       Q(t) = Q_o*e^(-0.000120968*t)                                    

7 0
3 years ago
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