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Sergio [31]
3 years ago
15

How much would $500 invested at 6% interest compounded continuously be worth after 5 years?

Mathematics
1 answer:
Montano1993 [528]3 years ago
5 0
A = Pert
500*e^(.06)(5) = $674.93
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Divide 33 into 2 groups so the ratio can be 4 to 7
svet-max [94.6K]
To do this task the best way is always add both "sides" of ratio and divide whole group by this sum.sum=4+7=1133:11=3Now we know how much is 1 and we can multiply by 4 and by 7 to find the answer.3*4=12 - first group3*7=21 - second group
Your result is ok.
7 0
2 years ago
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Please help anything is appreciated I will give you Brinley if it’s right
bearhunter [10]

I wish you good lessons

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3 years ago
Jan and Wayne went to the store to buy some groceries. Jan bought 2 cans of corn beef hash and 3 cans of creamed chipped beef fo
olasank [31]
You can solve this by using the system of equations.
Jan - 4.95 = 2H + 3C
Wayne - 5.45 = 3H + 2C

Use elimination.
-3(2H + 3C = 4.95)
2(3H + 2C = 5.45)

Solve. And you'll get:
-6H + (-9C) = -14.85
6H + 4C = 10.9

Cross out -6H and 6H because they cancel out. And you're left with:
-9C = -14.85
4C = 10.9

Add -9C with 4C, and -14.85 with 10.9.
-5C = -3.95

Divide each side with -5.
C = $0.79

Now to figure out what H is, just substitute the C in one of the equations with 0.79.
5.45 = 3H + 2(0.79)
5.45 = 3H + 1.58
-1.58            -1.58
3.87 = 3H
3.87/3 = 3/3(H)
1.29 = H

Finished!
7 0
3 years ago
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What’s the slope of y=4x+5
victus00 [196]

Answer:

4

Step-by-step explanation:

The slope is 4 because in the y=mx+b format m is always the slope while b is your initial value or starting point

3 0
2 years ago
The equation of line q is y = 1/3x-7Parallel to line q is liner, which passes through the
grigory [225]

Answer:

y =  \frac{1}{3} x - 10

Step-by-step explanation:

The equation of a line is usually written in the form of y=mx+c, where m is the gradient and c is the y-intercept.

Parallel lines have the same gradient. Hence the gradient of line r is \frac{1}{3}.

Susbt. m=\frac{1}{3},

y =  \frac{1}{3} x + c

To find c, substitute a coordinate.

When x=3, y= -9,

- 9 =  \frac{1}{3} (3) + c

-9= 1 +c

c= -9-1

c= -10

Thus the equation of line r is y =  \frac{1}{3} x - 10.

7 0
3 years ago
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