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Delvig [45]
3 years ago
13

What this simplified

Mathematics
1 answer:
kati45 [8]3 years ago
5 0

Answer:

\frac{3b\sqrt[3]{c^{2}} }{a^{2} }

Step-by-step explanation:

∛(27a⁻⁶b³c²)

To simplify, first apply the cube root the each of the terms. Keep in mind this rule: \sqrt[n]{a^{m}}  = (\sqrt[n]{a})^{m} = a^{m/n}

∛27 = 3    (because 3*3*3 = 27)

∛a⁻⁶ = a^{-6/3} = a^{-2} = \frac{1}{a^{2}}

∛b³ = b^{3/3} = b^{1} = b

∛c² = c^{2/3}

∛(27a⁻⁶b³c²)

= \frac{3b\sqrt[3]{c^{2}} }{a^{2} }

Simplified form generally follows these rules:

No negative exponents

No fraction exponents

Keep in fractional form

Reduce numerical values

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