The slant height of the pyramid can be calculated using Pythagoras theorem. Therefore, the slant height is 6.7 mm
<h3>How to find slant height of a pyramid?</h3>
The slant height x, can be found using Pythagoras theorem,
Therefore,
c² = a² + b²
where
- c = hypotenuse
- a and b are other two legs.
Therefore,
x² = 4.5² + 5²
x² = 20.25 + 25
x² = 45.25
x = √45.25
x = 6.72681202354
x = 6.7 mm
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Answer:
x=47
Step-by-step explanation:
75 I think since 75 divided by 3 equals 25
Answer:
54.28 cm²
Step-by-step explanation:
Area rectangle = 10 x 4 = 40 cm²
Area semicircle = 1/2(π(2²)) = 1/2(π(4)) = 2π ≈ 6.28 cm²
Area triangle = 1/2(4 x (10-14)) = 1/2( 4 x 4) = 2 x 4 = 8 cm²
Total Area = 40 cm² + 6.28 cm² + 8 cm² = 54.28 cm²
-Chetan K
Answer:
y = (-1/2)x + 9/2
Step-by-step explanation:
the equation of a straight line can be written as;
y = mx + c ......1
Where;
m = slope
c = intercept
For two lines to be perpendicular their slope must be opposite reciprocal of each other.
m1 × m2 = -1 .....2
Given;
The equation Contains (3, 3); and perpendicular to the line y = 2x - 1
Slope of the given equation m1 = 2
Slope of the line m2; substituting m1 to equation 2.
2 × m2 = -1
m2 = -1/2
So,
y = (-1/2)x + c
To solve for c, let's substitute the given point on the line; (3,3).
3 = (-1/2)(3) + c
3 = -3/2 + c
c = 3 + 3/2
c = 9/2
Therefore, the equation of the line that has the given properties is;
y = (-1/2)x + 9/2