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ki77a [65]
3 years ago
12

Once a year, a store offers a free frozen yogurt to its customers. Each customer can choose one flavor of frozen yogurt and one

topping. There are 8 possible ways to order the frozen yogurt. How many flavors and toppings could the customers choose from?
A: 2 flavors and 2 toppings
B: 2 flavors and 4 toppings
C: 4 flavors and 3 toppings
D: 4 flavors and 4 toppings
Mathematics
2 answers:
goldenfox [79]3 years ago
8 0

Answer:

Step-by-step explanation:

B

Alex73 [517]3 years ago
7 0

Answer:

HERE YA GO MA BOO, lol just messin dont hate

The answer is B

Step-by-step explanation:

2 times 4 = 8

Kono Dio Da!!!

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Solve the Equation. What is b?
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Answer:

Solution :

                  b = 4

Step-by-step explanation:

Rearrange first.

                    4*b+5-(1+5*b)=0  

Step by step solution :

Step  1:  We are Solving a Single Variable Equation :

Solve :    -b+4 = 0  

Step 2: Subtract  4  from both sides of the equation :  

                     -b = -4

Step 3: Multiply both sides of the equation by (-1):  

Final answer is <em><u>b = 4</u></em>

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<u><em>Brainliest please, I need 4 more :P</em></u>

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4 years ago
A rectangle is 12 feet long and 34 feet wide what is the area of the rectangle enter your answer in the box as a fraction in sim
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4 years ago
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The Mans age is 41 sorry I can't give me expression
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3 years ago
Okay i have two 'true or false' questions from algebra 1:
rusak2 [61]
1.) False
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5 0
3 years ago
In choosing what music to play at a charity fund raising event, Cory needs to have an equal number of piano sonatas from Mozart,
hram777 [196]

Answer:

We conclude that have 96390 different schedules.

Step-by-step explanation:

We know that In choosing what music to play at a charity fund raising event, Cory needs to have an equal number of piano sonatas from Mozart, Brahms, and Schubert.  If he is setting up a schedule of the 6 piano sonatas to be played, and he has 18 Mozart, 3 Brahms, and 21 Schubert piano sonatas.  

We calculate  how many different schedules are possible:

C_2^{18}\cdot C_2^3\cdot C_2^{21}=\frac{18!}{2!(18-2)!}\cdot \frac{3!}{2!(3-2)!}\cdot \frac{21!}{2!(21-2)!}=96390

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3 0
3 years ago
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