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r-ruslan [8.4K]
4 years ago
5

What is an equal equation to (2b+1)-b

Mathematics
1 answer:
makvit [3.9K]4 years ago
4 0

To have an equation, you need to have two expression, and an equal sign (=) between them.

This is not an equation, but rather an expression. In order to simplify it, you simply have to subtract b from the quantity in the parenthesis:

(2b+1)-b = 2b+1-b = 2b-b+1 = b+1

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HELP QUICK!!!! NOW!!!!
inessss [21]

Answer: B. 2,448π units³

Step-by-step explanation:

     We will use the formula for the volume of a cylinder to solve.

(<em>The formula, put simplify, finds the area of the base circle and multiples by the height.</em>)

V = πr²h

V = π(12)²(17)

V = (144)(17)π

V = 2,448π

       The volume is 2,448π units³ which is option B for your problem.

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2 years ago
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Help me please I. Need help is this right?
Alex73 [517]

it’s b 3/4 hours because when you split 1 1/2 in half it’s like if you split 150 into 75

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3 years ago
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What is 9/18 simplified
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1/2 9 goes into 18, 2 and 9 goes into 9 once. 
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3 years ago
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What is an equation of the line that is perpendicular to y+1=-3(x-5) and passes through the point 4,-6
Oliga [24]

Answer:

y=\frac{1}{3}x-\frac{16}{3}

Step-by-step explanation:

Arranging the given equation in slope-intercept form ( y = mx + b ):

y+1=-3(x-5)\\y+1=-3x+15\\y=-3x+15-1\\y=-3x+14

<em>We know that the perpendicular line would have a slope (m) that is </em><em>negative reciprocal </em><em>of this (\frac{1}{3}). Thus we can write the perpendicular line's equation as  y=\frac{1}{3}x+b. </em>

<em />

<em>Now putting x = 4 and y = -6 into the equation, we can solve for b:</em>

<em>y=\frac{1}{3}x+b\\-6=\frac{1}{3}(4)+b\\-6=\frac{4}{3}+b\\b=-6-\frac{4}{3}\\b=-\frac{16}{3}</em>

<em />

Thus, the equation of the perpendicular line is  y=\frac{1}{3}x-\frac{16}{3}

6 0
3 years ago
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Select the correct answer from each drop-down menu. Quadrilateral PQRS, with vertex P(-5, -3), undergoes a transformation to for
anygoal [31]

Answer:

i) A. 180º rotation about the origin, ii) Q' = (4, 5).

Step-by-step explanation:

i) In this case, we understand that vertex P = (-5,-3) changed to P' = (5,3) after doing an operation. At first we must calculate the distance of each point regarding origin by Pythagorean Theorem:

Point P:

OP = \sqrt{(x_{P}-x_{O})^{2}+(y_{P}-y_{O})^{2}}

If we know that x_{P} = -5, y_{P} = -3, x_{O} = 0 and y_{O} = 0, the distance OP is:

OP = \sqrt{(-5-0)^{2}+(-3-0)^{2}}

OP \approx 5.831

Point P':

OP' = \sqrt{(x_{P'}-x_{O})^{2}+(y_{P'}-y_{O})^{2}}

If we know that x_{P'} = 5, y_{P'} = 3, x_{O} = 0 and y_{O} = 0, the distance OP' is:

OP' = \sqrt{(5-0)^{2}+(3-0)^{2}}

OP' \approx 5.831

As OP = OP', origin is the center of rotation.

Besides, P' is a multiple of P, that is:

1) (-5, -3) Given

2) ((-1)\cdot 5, (-1)\cdot 3) (-a)\cdot b = -a\cdot b

3) (-1)\cdot (5, 3) Scalar multiplication of a vector/Result.

The value of the scalar proves that P experimented a 180º rotation about the origin. Hence, the correct answer is A.

ii) If Q = (-4, -5) and the same operation described in item i) is used, then, the location of Q' is:

Q' = (-1)\cdot Q

Q' = (-1) \cdot (-4,-5)

Q' = ((-1)\cdot (-4), (-1)\cdot (-5))

Q' = (4, 5)

Which corresponds to option C.

7 0
3 years ago
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