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nordsb [41]
3 years ago
13

Need help plz. Algebra 1 Y = 3X^2

Mathematics
1 answer:
ss7ja [257]3 years ago
5 0

Answer:

Step-by-step explanation:

plz give brainliest

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Which statement is false?
Luda [366]

Answer:

A.

Step-by-step explanation:

1/5 is a rational number so A is false. Just to prove this ill show every other answer is true.

B is true because rational; numbers have a repeating pattern while irrational do not.

C is true as any number not involving i is a real.

D is true as all integers have a repeating pattern if turned into decimal form.

4 0
3 years ago
Jessica made 4 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for all 4 necklace
valentina_108 [34]

Answer:

If the total cost of the 4 necklaces was 18.40 then that means in order to find out how much she spent on pendents she needs to subtract the amount of beads from from the total cost so,

18.40-11.20=7.20

And cause she made 4 necklaces she is going to need to divide 7.20 by 4 to find out the cost of money that she had spent on each necklaces pendants.

7.20÷4=1.80

Meaning that she had spent $1.80 on each necklaces pendants

7 0
3 years ago
Which congruence theorem can be used to prove bda = bdc <br><br>Hl<br>ssa <br>aas <br>sss
ozzi
Given that ΔBDA is similar to ΔBDC and:
AD≡DC
AB≡BC
BD≡BD (shared side)
then the best postulate to use is the side-side-side (SSS) postulate.
Answer: SSS
4 0
3 years ago
Read 2 more answers
If a number is divisible by 2, then the number ends with a 2. which of the following best describes a counter example to the con
Thepotemich [5.8K]
Answer: 44
Explanation: it is divisible by two but does not end with two
6 0
3 years ago
Which answer is equivalent to<br> ??? Help please
grigory [225]

Answer:

\large\boxed{\dfrac{36}{25}}

Step-by-step explanation:

\text{Use}\ a^{-n}=\dfrac{1}{a^n}\\\\\dfrac{5^{-2}\cdot9}{2^4\cdot4^{-3}}=(5^{-2}\cdot9):(2^4\cdot4^{-3})=\left(\dfrac{1}{5^2}\cdot9\right):\left(2^4\cdot(2^2)^{-3}\right)\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\left(\dfrac{1}{25}\cdot9\right):(2^4\cdot2^{-6})\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\dfrac{9}{25}:2^{4+(-6)}=\dfrac{9}{25}:2^{-2}=\dfrac{9}{25}:\dfrac{1}{2^2}=\dfrac{9}{25}:\dfrac{1}{4}=\dfrac{9}{25}\cdot\dfrac{4}{1}=\dfrac{36}{25}

7 0
3 years ago
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