Answer:
<h3>On a coordinate plane, a cube root function goes through (negative 8, negative 2), has an inflection point at (0, 0), and goes thorugh (8, 2).</h3>
Step-by-step explanation:
![f(x)=\sqrt[3]{x}\\\\f(-8)=\sqrt[3]{-8}=-2\to(-8,\ -2)\\\\f(0)=\sqrt[3]{0}=0\to(0,\ 0)\\\\f(8)=\sqrt[3]{8}=2\to(8,\ 2)\\\\\\\sqrt[3]{a}=b\iff b^3=a\\\\\text{Therefore:}\\\\\sqrt[3]{-8}=-2\ \text{because}\ (-2)^3=-8\\\sqrt[3]0=0\ \text{because}\ 0^3=0\\\sqrt[3]{8}=2\ \text{because}\ 2^3=8](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D%5C%5C%5C%5Cf%28-8%29%3D%5Csqrt%5B3%5D%7B-8%7D%3D-2%5Cto%28-8%2C%5C%20-2%29%5C%5C%5C%5Cf%280%29%3D%5Csqrt%5B3%5D%7B0%7D%3D0%5Cto%280%2C%5C%200%29%5C%5C%5C%5Cf%288%29%3D%5Csqrt%5B3%5D%7B8%7D%3D2%5Cto%288%2C%5C%202%29%5C%5C%5C%5C%5C%5C%5Csqrt%5B3%5D%7Ba%7D%3Db%5Ciff%20b%5E3%3Da%5C%5C%5C%5C%5Ctext%7BTherefore%3A%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B-8%7D%3D-2%5C%20%5Ctext%7Bbecause%7D%5C%20%28-2%29%5E3%3D-8%5C%5C%5Csqrt%5B3%5D0%3D0%5C%20%5Ctext%7Bbecause%7D%5C%200%5E3%3D0%5C%5C%5Csqrt%5B3%5D%7B8%7D%3D2%5C%20%5Ctext%7Bbecause%7D%5C%202%5E3%3D8)
25d^2-30d-35d+42=25d^2-65d+42.
Answer:
This cannot be simplified any further. That is the simplest you'll get.
Yes, because to be in congruent with something means to have the same shape and size.
Hope this helps!