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vazorg [7]
3 years ago
15

In a parking lot, there are 21 blue cars and 75 cars that are other colors. What is the ratio of blue cars to cars that are not

blue?
Mathematics
2 answers:
blondinia [14]3 years ago
8 0
The ratio would be 21:75
Stella [2.4K]3 years ago
6 0
Fraction form? 21/75 which should be reduced to 7/25
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Help on this one as well
SashulF [63]
The answer is 6.375 hope it help
8 0
3 years ago
Joy drank 2 3 liter of water Monday before going jogging. She drank 5 7 liter of water after her jog. How much water did Joy dri
Alexxandr [17]

Answer: 1 ⁸/₂₁ litres

Step-by-step explanation:

First find a common multiple to enable you add them up:

= 21

21 will be the denominator.

Multiply each numerator by the number you get when you divide 21 by the denominator.

= 21/3 = 7

= 7 * 2 = 14

= 21/7 = 3

= 3 * 5

= 15

= \frac{14 + 15}{21} \\\\= \frac{29}{21}

= 1\frac{8}{21} litres

8 0
2 years ago
What is the measure of Angle Y?
ivolga24 [154]

Answer:

62 degrees

Step-by-step explanation:

180 - (65 + 53) =

180 - 118 =

62 degrees

Hope that helps!

3 0
3 years ago
Two angles that are supplementary are always linear pair true or false?
insens350 [35]
The answer would be True
5 0
2 years ago
a parabola has an x-intercept at 2, its axis of symmetry is the line x=4, and the y-coordinate of its vertex is 6. Determine the
nlexa [21]

Answer:

The standard equation of the parabola is:

y=-\frac{3}{2}x^2+12x-18

Step-by-step explanation:

An x intercept of 2 means that the point (2, 0) is in the graph of the parabola.

We can also write the general expression for the parabola in vertex form, since we can use the information on the coordinates of the vertex: (4, 6) - recall that the axis of symmetry of the parabola goes through the parabola's vertex, so the x-value of the vertex must be x=4.

y-y_{vertex}=a\,(x-x_{vertex})^2\\y-6=a\,(x-4)^2

Now we can find the value of the parameter "a" by using the extra information about the point (2, 0) at which the parabola intercepts the x-axis:

y-6=a\,(x-4)^2\\0-6=a\,(2-4)^2\\-6=a\,4\\a=-\frac{6}{4} =-\frac{3}{2}

Then the equation of the parabola becomes:

y-6=-\frac{3}{2} \,(x-4)^2\\y-6=-\frac{3}{2} (x^2-8x+16)\\y-6=-\frac{3}{2}x^2+12x-24\\y=-\frac{3}{2}x^2+12x-18

7 0
3 years ago
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