Question

The function E(d)=0.25d√ approximates the number of seconds it takes a dropped object to fall d feet on Earth. The function J(d)=0.64⋅E(d) approximates the number of seconds it takes a dropped object to fall d feet on Jupiter. How long (in seconds) does it take a dropped object to fall 50 feet on Jupiter? Round your answer to the nearest hundredth.

Answer 1

Answer:

1.13 seconds

Step-by-step explanation:

step 1

Find out how (in seconds) does it take a dropped object to fall 50 feet on Earth

we have

$E(d)=0.25\sqrt{d}$

we have

$d=50\ ft$

substitute

$E(50)=0.25\sqrt{50}\ sec$

step 2

Find out how (in seconds) does it take a dropped object to fall 50 feet on Jupiter

we have

$J(d)=0.64E(d)$

For

$d=50\ ft$

$J(50)=0.64E(50)$

Remember that

$E(50)=0.25\sqrt{50}\ sec$

substitute

$J(50)=0.64(0.25\sqrt{50})=1.13\ sec$