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Alenkasestr [34]
4 years ago
5

The function E(d)=0.25d√ approximates the number of seconds it takes a dropped object to fall d feet on Earth. The function J(d)

=0.64⋅E(d) approximates the number of seconds it takes a dropped object to fall d feet on Jupiter. How long (in seconds) does it take a dropped object to fall 50 feet on Jupiter? Round your answer to the nearest hundredth.
Mathematics
1 answer:
vladimir1956 [14]4 years ago
8 0

Answer:

1.13 seconds

Step-by-step explanation:

step 1

Find out how (in seconds) does it take a dropped object to fall 50 feet on Earth

we have

E(d)=0.25\sqrt{d}

we have

d=50\ ft

substitute

E(50)=0.25\sqrt{50}\ sec

step 2

Find out how (in seconds) does it take a dropped object to fall 50 feet on Jupiter

we have

J(d)=0.64E(d)

For

d=50\ ft

J(50)=0.64E(50)

Remember that

E(50)=0.25\sqrt{50}\ sec

substitute

J(50)=0.64(0.25\sqrt{50})=1.13\ sec

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