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egoroff_w [7]
3 years ago
5

Find the samllest value of K when : 280k is a perfect square 882 is a cube

Mathematics
1 answer:
adoni [48]3 years ago
5 0
280 = 7 x 2^3 x 5
882 = 7^2 x 2 x 3^2

For 280k to be perfect square , their powers need to be even
For 882 to be a cube, their powers need to be in multiple of 3,

To satisfy both parties,
K = 7 x 2^5 x 3^4 x 5^3 = 2268000
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I guess since you have the correct answer there that you need to know how to get it. Start by rewriting that exponent as a radical. It would look like this: \sqrt{(8x-8)^3}=64. The first step is to undo that square root by squaring both sides. That will give you this: (8x-8)^3=4096. Next we have to undo that cubing by taking the cubed root of both sides, leaving us with this: 8x-8=16. We add 8 to both sides to get 8x = 24 and x = 3.

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kvv77 [185]

Answer:

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6 0
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What is 0.01 rounded to the nearest hundredth
Novosadov [1.4K]

Answer:

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Step-by-step explanation:

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I'LL GIVE BRAINLIEST HELP
OLga [1]

Hey!

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Part A:

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Part B:

40 - 40 = 0 overtime hours.

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48 - 40 = 8 overtime hours.

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