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4 years ago

8

The average NBA ticket price for the 2018-2019 season is up 14.01% from the average ticket price of $78 during the 2015-2016 sea

son. what is the average ticket price in 2018-2019? Round to the nearest penny.

1 answer:

sattari [20]4 years ago

8 0

Answer:

$88.93

Step-by-step explanation:

78 * 1.1401 = $88.93

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How many pints are in One 11/4 miles

Lostsunrise [7]

3.303e+13 that is approximately

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3 years ago

Mika is a local farmer who is interested in how often residents in her town go to a farmer's market each month. She surveys 124

TEA [102]

Answer:

The margin of error is of 0.3012, and it means that we should be 99% confident that the population mean would be within 0.3012 of the sample mean.

Step-by-step explanation:

Margin of error

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation and n is the size of the sample.

Standard deviation of 1.3

This means that $\sigma = 1.3$

She surveys 124 families

This means that $n = 124$

Margin of error and meaning:

$M = z\frac{\sigma}{\sqrt{n}}$

$M = 2.58\frac{1.3}{\sqrt{124}}$

$M = 0.3012$

The margin of error is of 0.3012, and it means that we should be 99% confident that the population mean would be within 0.3012 of the sample mean.

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2 years ago

Jordi trains on his bicycle by riding for a total of 300 miles each week

Katen [24]

Y = 300 (miles) * x (independent variable)
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3 years ago

PLEASE HELP URGENT 10 POINTS

snow_tiger [21]

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2 years ago

Read 2 more answers

A pyramid-shaped vat has square cross-section and stands on its tip. The dimensions at the top are 2 m × 2 m, and the depth is 5

Strike441 [17]

Answer:

the water level increases at a rate of 1.718 m/min when the depth is 4 m

Step-by-step explanation:

the volume of the pyramid is

V = (1/3)(height)(area of base) = 1/3 H*L²

For the diagonal in the pyramid

tg Ф = Side Length/ Height = L / H = x / h

where h= depth of water , x= side of the corresponding cross section

therefore x= L *h/H

the volume of the water is

v= 1/3 h*x² = 1/3 (L/H)² h³

in terms of time

v = Q*t

then

Q*t = 1/3 (L/H)² h³

h³ = 3*(H/L)² *Q *t

h = ∛(3*(H/L)² *Q *t) = ∛(3*(H/L)² *Q) *∛t = k* ∛t , where k=∛(3*(H/L)² *Q)

h = k* ∛t

then the rate of increase in depth is dh/dt

dh/dt = 1/3*k* t^(-2/3)

since

t = (h/k)³

dh/dt = 1/3*k* t^(-2/3) = 1/3*k* (h/k)³ ^(-2/3) = 1/3*k* (h/k)^(-2) = 1/3 k³ / h²

= 1/3 (3*(H/L)²*Q) / h² = (H/L)²*Q /h²

dh/dt= [H/(h*L)]²*Q

replacing values, when h=4m

dh/dt= [H/(h*L)]²*Q = [5m/(4m*2m)]² * (3m³/min)= 1.718 m/min

8 0

3 years ago