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DIA [1.3K]
3 years ago
11

What is the value of 'c' so that -9 and 9 are both solutions of x^2+c=103?

Mathematics
2 answers:
kotykmax [81]3 years ago
8 0

Answer:

c = 22

Step-by-step explanation:

Remark

You have to make c large enough so that when subtracted from 103, you get 81

Solution

x^2 + c = 103

x = 9

9^2 + c = 103

81 + c = 103

Subtract 81 from both sides

81 - 81 + c = 103 - 81

c = 22

- 9 does exactly the same thing.

Check

x^2 + 22 = 103

x^2 - 22 = 103 - 22

x^2 = 81

sqrt(x^2) = sqrt(81)

x = +/- 9

Gnoma [55]3 years ago
4 0

Answer:

c = 22

Step-by-step explanation:

x^2 + c = 103 so if x is either + or - 9, x^2 = 81 so...

81 + c = 103

c = 22

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The measure of one angle is six more than half the measure of another angle. If the angles are complementary, find both measures
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Answer:

The measures of the two angles are 34° and 56°

Step-by-step explanation:

* Lets explain how to solve the problem

- The complementary angles are the angles whose the sum

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- Let the measure of the second angle angle is x

∵ The measure of the 2nd angle is x

∵ The measure of the first angle is 6 more than the half of the

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∴ x = 56

∵ x is the measure of the 2nd angle

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∵ The measure of the 1st angle = 6 + 1/2 x

∵ x = 56

∴ The measure of the 1st angle = 6 + 1/2(56) = 34°

* The measures of the two angles are 34° and 56°

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