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DIA [1.3K]
3 years ago
11

What is the value of 'c' so that -9 and 9 are both solutions of x^2+c=103?

Mathematics
2 answers:
kotykmax [81]3 years ago
8 0

Answer:

c = 22

Step-by-step explanation:

Remark

You have to make c large enough so that when subtracted from 103, you get 81

Solution

x^2 + c = 103

x = 9

9^2 + c = 103

81 + c = 103

Subtract 81 from both sides

81 - 81 + c = 103 - 81

c = 22

- 9 does exactly the same thing.

Check

x^2 + 22 = 103

x^2 - 22 = 103 - 22

x^2 = 81

sqrt(x^2) = sqrt(81)

x = +/- 9

Gnoma [55]3 years ago
4 0

Answer:

c = 22

Step-by-step explanation:

x^2 + c = 103 so if x is either + or - 9, x^2 = 81 so...

81 + c = 103

c = 22

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3 years ago
What are the critical points for the inequality 2x+5/x-2≥x-1/x-2?
Pachacha [2.7K]
1) When the denominator equals zero that is a critical point

=> x - 2 = 0 => x = 2.

So x = 2 is a critical point

2) Simplify the numerator to find an expresion of the king p(x) ≥ 0 or p(x) ≤ 0. Where p(x) equals zero you have other(s) critical point(s)

Multiply both terms:

[2x + 5] / [ x - 2] = [x - 1] / [x - 2]

for x ≠ 2 => 2x + 5 = x - 1

=> 2x - x = - 1 - 5

=> x = - 6

Then, the two critical points are x = 2 and x = - 6.

Answer: option B.
3 0
3 years ago
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Ulleksa [173]

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C

Step-by-step explanation:

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2 years ago
How many terms are there in v/3 + 2 x 5
sammy [17]

Answer:1

Step-by-step explanation:

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6 0
2 years ago
How do you subtract an integer from another integer without using a number line or counters
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I'm assuming you mean negative integers and mixed. -3--3=? When to negatives are back to back it turns in to a positive number. The equation becomes -3+3=0.

Adding 2 negative numbers will always result in a negative value. -3+-3=-6.

A negative times a negative is always a positive . -2x-2=4

A positive integer times a negative integer will be a negative value. -3x4=-12.

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3 years ago
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