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Sever21 [200]
3 years ago
15

Find an equation of the line passing through each of the following pairs of points. a (−3, 1), (0, 3)

Mathematics
1 answer:
Svetlanka [38]3 years ago
5 0

\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-3)}}}\implies \cfrac{2}{0+3}\implies \cfrac{2}{3}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{2}{3}}[x-\stackrel{x_1}{(-3)}]\implies y-1=\cfrac{2}{3}(x+3) \\\\\\ y-1=\cfrac{2}{3}x+2\implies y=\cfrac{2}{3}x+3

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You have 8,640 grams of a radioactive kind of cesium. If its half-life is 30 years, how much
Vikki [24]

The mass of cesium left afer 120 years if the original mass of cesium is 8640 with an half-life of 30 years,  is 540 grams.

<h3>What is half-life?</h3>

This can be defined as the time taken for half the amount of a radioactive substance to decay.

To calculate the amount of cesium left after 120 years, we use the formua below.

Formula:

  • R' = R/(2^{T/t})............. Equation 1

Where:

  • R = Original amount of Cesium
  • R' = New amount of cesium
  • T = Total time
  • t = Half-life

From the question,

Given:

  • R = 8640
  • T = 120 years
  • t = 30 years

Substitute these values into equation 1

  • R' = 8640/(2^{120/30})
  • R' = 8640/2^{4}
  • R' = 8640/16
  • R' = 540 grams.

Hence, The mass of cesium left afer 120 years is 540 grams.

Learn more about half-life here: brainly.com/question/25750315

4 0
2 years ago
Slope intercept form of 7x-2y=-8
Vlada [557]

7x-2y=-8

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5 0
3 years ago
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A carnival is being set up in your hometown. From experience, the carnival organizer knows that the amount of money he will brin
pentagon [3]

Answer:

$6,200

Step-by-step explanation:

The question is to find the expected value.

We know the expected value of a scenario is the sum of the products of each probability of event and its profit or loss.

There are 3 probabilities in the scenario:

Rainy: 20% = 20/100 = 0.2

Sunny: 50% = 50/100 = 0.5

Cloudy: Rest, which is 100 - (50+20) = 100 - 70 = 30% = 30/100 = 0.3

Now, the gain and loss is:

Rainy: Lose 5000 means -5000

Cloudy: Gain 4000 means +4000

Sunny: Gain 12,000 means +12,000

Now, the expected value is:

Expected Value = (0.2)(-5000) + (0.5)(12000) + (0.3)(4000) =  $6,200

8 0
3 years ago
Help please please need quick
timama [110]
14 times 14=196
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The length of X is approximately 7 root 3. Or 12.12 as a decimal
8 0
2 years ago
 The members of the city cultural center have decided to put on a play once a night for a week. Their auditorium holds 500 peopl
konstantin123 [22]

Answer: In first question, Number of student's ticket(s) = 400

And number of adult's ticket(d) = 100

In second question, The goal of $3050 fell by $710

Step-by-step explanation:

1. Since, Here d represents the number of adult tickets and s represents the number of student tickets.

And, all 500 seats are filled for a​ performance.

Therefore, s + d = 500 ------(1)

Also, the price of one adult's  ticket = $8.50

The price of one student's ticket= $5.50

And, their is a revenue of $3050 by selling the tickets.

Thus, 8.50 d + 5.50 s = 3050 --------(2)

By solving the equation (1) and equation (2),

we get, s = 400, d=100

Thus, Number of student's ticket(s) = 400

And number of adult's ticket(d) = 100

2. According to the question,

s = 2 d  ----- (3)

s + d = 360 -----(4)

By solving equation (3) and (4),

We get, s = 240 and d = 120

thus, the total revenue after selling 360 tickets = 8.50 × 120 + 5.50 × 240 = $2340

But, the goal is $3050 ( according to the question)

Thus the total fall = 3050 - 2340 = $710

6 0
3 years ago
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