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svp [43]
3 years ago
13

I need help quick, its super hard

Mathematics
2 answers:
faltersainse [42]3 years ago
5 0

Answer:

Q

Step-by-step explanation:

The nearest perfect square of sqrt10 is sqrt9 and sqrt 16, representing a 3 and 4.

Thus, we can conclude that sqrt10 is between 3 and 4.

Notice sqrt 10 is very close with sqrt9 than sqrt16, it should be closer to 3 rather than 4.

The only point that fits the context is Q

Hunter-Best [27]3 years ago
4 0
The guy above me is correct
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Which variable will you choose to eliminate? How? -3x -8y=-24 and <br> 3x - 5y= 45
Jet001 [13]

Answer:

Lets choose y

  • -8y=3x-24
  • y=-3/8x+3

Plug in

  • 3x+15/8x-15=45
  • 39/8x= 60
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3 0
3 years ago
Read 2 more answers
The Changs received a delivery of fuel oil totaling 35.00 gallons. The oil cost $3.05 per gallon. What did the Changs pay for th
Ede4ka [16]

Answer:

$106.75

Step-by-step explanation:

Since the cost of a gallon of oil cost $3.05, we are going to have the equation y = 3.05x, where x represents the number of gallons of oil.

Since the Changs have 35 gallons of oil, the equation would be;

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7 0
2 years ago
The area rug is 4 15/32 square meters. The rug is 2 3/4 meters in length. How wide is the rug
Whitepunk [10]
Steps:
1. To do this problem, you have to divide the area by the length
2. To make this easier, turn both numbers into improper fractions
143/32 divided by 11/4
3. To divide you actually have to multiply by the reciprocal
143/32 times 4/11 equals 572/352
4. Turn 572/352 into a mixed number which is 1 220/352
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6. Your answer is.
1 5/8

6 0
3 years ago
Help asap will give brainliest to whoever answer's correctly.
nydimaria [60]

Answer:

cant see the image

Step-by-step explanation:

8 0
2 years ago
Find the error with this proof and explain how it mat be corrected in order to clearly prove the equation.
enyata [817]

Answer:

Step-by-step explanation:

It is true that for any given odd integer, square of that integer will also be odd.

i.e if m is and odd integer then m^{2} is also odd.

In the given proof the expansion for (2k + 1)^{2} is incorrect.

By definition we know,

(a+b)^{2} = a^{2} + b^{2} + 2ab

∴ (2k + 1)^{2} = (2k)^{2} + 1^{2} + 2(2k)(1)\\(2k + 1)^{2} = 4k^{2} + 1 + 4k

Now, we know 4k^{2} and 4k will be even values

∴4k^{2} + 1 + 4k will be odd

hence (2k + 1)^{2} will be odd, which means m^{2} will be odd.

7 0
3 years ago
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