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3 years ago

The table below shows two equations:

Mathematics

1 answer:

Setler [38]3 years ago

4 0

The answer is a

i hope this helps

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Solve the system using any method. Show your work.<br> { 3 x + y = 4<br> − 3 x − y = − 8

prisoha [69]

Answer:

No solution

Step-by-step explanation:

3 x + y = 4 (1)

− 3 x − y = − 8 (2)

Add (1) and (2)

0 + 0 = -4

0 = -4 is a false statement

So, no solution

5 0

3 years ago

Solve (x – 3)2 = 49. Select the values of x. –46 -4 10 52

Fudgin [204]

Answer: x = 55/2

Step-by-step explanation: (x)(2) (-3)(2) = 49 2x-6+6 = 49+6 2x/2 = 55/2 x = 55/2

I know that my answer isn't a choice for one of the values of x but that's the result that I got when I solved (x–3)2 = 49.

6 0

3 years ago

Factorise 15x-5 <br> factorise x^2-5x+6

kotegsom [21]

5(3x-1) (x-3)(x-2) I don't know if you want working out or an explanation? Or if it's too late, sorry.

5 0

3 years ago

Put<br> 4y+x=-1 into y-intercept form and show how you did it.

artcher [175]

4y+x= -1
-x -x
—————
4y=-x-1
— ——
4 4
=======
Y= -1/4x - 1/4
Hoped this helps

3 0

3 years ago

A square of side length s lies in a plane perpendicular to a line L. One vertex of the square lies on L. As this square moves a

user100 [1]

Answer:

Part (A) The required volume of the column is $s^2h$ .

Part (B) The volume be $s^2h=\frac{s^2h}{2}+\frac{s^2h}{2}$ .

Step-by-step explanation:

Consider the provided information.

It is given that the we have a square with side length "s" lies in a plane perpendicular to a line L.

Also One vertex of the square lies on L.

Part (A)

Suppose there is a square piece of a paper which is attached with a wire through one corner. As you blow it up it spins around on the wire.

This square moves a distance h along L, and generate a corkscrew-like column with square.

The cross section will remain the same.

So the cross section area of original column and the cross section area of twisted column at each point will be the same.

The volume of the column is the area of square times the height.

This can be written as:

$s^2h$

Hence, the required volume of the column is $s^2h$ .

Part (B) What will the volume be if the square turns twice instead of once?

If the square turns twice instead of once then the volume will remains the same but divide the volume into two equal part.

$s^2h=\frac{s^2h}{2}+\frac{s^2h}{2}$

Hence, the volume be $s^2h=\frac{s^2h}{2}+\frac{s^2h}{2}$ .

5 0

3 years ago