A certain fungus grows in a circular shape. Its diameter in inches after t weeks is given below 6 -(50/t^2+ 10). What is the squ
are inches at the end of 5 weeks?
1 answer:
The answer is 5.2π in² = 16.3 in²
The area (A) of the circle with radius r is: A = r²π
It is known:
π = 3.14


t = 5
⇒

A = r²π = (16/7)²π = (2.28)²π = 5.2π = 5.2 · 3.14 = 16.3 in²
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