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mr_godi [17]
3 years ago
11

Find the missing value to the nearest hundredth. sin __ = 8/15

Mathematics
2 answers:
ivann1987 [24]3 years ago
7 0
Sin-1(8/15)=32.23 so sin(32.23)=8/15. Hope this helps!
Sedaia [141]3 years ago
3 0
Sin32.23= 8/15. This is the answer. I checked on the calculator
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The interval for which is non real is
scZoUnD [109]

Answer:

c

Step-by-step explanation:

it is non real if x²-36<0

x²<36

|x|<6

so -6<x<6

7 0
3 years ago
Will mark Brainlest!! <br>Help Please!<br>(1). find the domain and range of the following <br>​
miss Akunina [59]

Answer:

Step-by-step explanation:

You have the domain. It is given as -1≤x≤1

Now all you have to do is figure out the range which is the y value. At first glance I think it might be 3, but that does not look very logical. I'll post this much of it now and be back in under an hour with a more complete answer.

Of course! How silly of me. There is a minimum of y = 1 in the range which comes from x = 0

I've included a graph so you can see how this all works.

So the range = 1 ≤ y ≤ 3

5 0
3 years ago
Find the surface area. round to the nearest hundredth when necessary.
Dmitry_Shevchenko [17]

Answer:

The surface area of the cuboid is 648 m^2

Step-by-step explanation:

What we have here is cuboidal in outlook

By using the formula for the surface area of a cuboid, we can get the surface area of the shape

mathematically, we have the surface area of a cuboid as follows;

2(lb + lh + bh)

where l is the length, b is the breadth (width) and h is the height

We can have the length as 9 m, the width as 9 m and the height as 13.5 m

Substituting these values, we have the surface area of the cuboid as;

A = 2(9(9) + 9(13.5) + 9(13.5))

A = 2(81 + 243)

A= 2(324)

A = 648 m^2

8 0
3 years ago
Determine the equations of the vertical and horizontal asymptotes, if any, for y=x^3/(x-2)^4
djverab [1.8K]

Answer:

Option a)

Step-by-step explanation:

To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty

Then. x = 2 it's a vertical asintota.

To obtain the horizontal asymptote of the function take the following limit:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4}

if \lim_{x \to \infty}\frac{x^3}{(x-2)^4} = b then y = b is horizontal asymptote

Then:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4} \\\\\\lim_{x \to \infty}\frac{1}{(\infty)} = 0

Therefore y = 0 is a horizontal asymptote of f(x).

Then the correct answer is the option a) x = 2, y = 0

3 0
3 years ago
Read 2 more answers
A tourist purchases a car in england and ships it home to the united states. the car sticker advertised that the car's fuel cons
Valentin [98]

<u>Solution-</u>

Fuel consumption rate = 40 miles per UK gallon (As the car is manufactured in UK)

1 UK gallon = 4.5459631 lit

1 US gallon = 3.7853060 lit

\therefore \frac{1 \ UK \ gallon}{1 \ US \ gallon} = \frac{4.5459631}{3.7853060} = 1.2009499

\Rightarrow 1 \ UK \ gallon = 1.2009499 \ US \ gallon

As the fuel consumption rate = 40 miles per gallon

⇒ You need 1 UK gallon of fuel to go 40 miles

⇒ You need 1.2009499 US gallon of fuel to go 40 miles

Or you can say that, to go 40 miles you need 1.2009499 US gallon of fuel

⇒ To go 1 mile you will need  \frac{1.2009499}{40} = 0.0300237

⇒ To go 738 miles you will need 0.0300237×738 = 22.1574906 US gallon of fuel

∴ 22.1574906 gallon of fuel is actually required.

∴ But, what she thinks will require is \frac{738}{40} = 18.45 gallons (As she calculated using UK gallons)

6 0
3 years ago
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