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Alona [7]
4 years ago
7

In regards to storing folders the computer can be described as a ________________.

Computers and Technology
1 answer:
Butoxors [25]4 years ago
7 0
A computer can be described as a "unit of storage". Its like a file cabinet, but digitally stored instead of a physical folder. Of course, space on a computers hard drive isn't unlimited. <span />
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Research and discuss the similarities and differences between cloud computing and client-server computing. Discuss the pros and
harkovskaia [24]

Answer:

Cloud computing as a virtual hosting tool, is much more theoretical. Both servers, applications, and communications are hosted in the cloud, off property, rather than being available via computer machine whereas In computing client/server, a controller gets client requests mainframes and needs to share its services, programs and/or data of one sometimes more client systems on the internet, and a client would be a portable platform that specific portions with a server and make use of a finite resource.

Explanation:

<u>Similar to cloud computing and client-server computing: - </u>

  • The cloud computing and client-server networking underpinning principles are the same. That is contact between client and server.
  • Throughout networking and client-server networking, user nodes can communicate (queries) with databases that live locally or are located in many other networks.

<u>Difference between computing and client-server computing: </u><u>- </u>

Resources: -

  • In computing client-server, the corporation or association controls the tools.
  • The services are offered in cloud computing by third parties or other businesses.

<u>The purpose of cloud computing and client-server computing is different:- </u>

  • Client-server computing is targeted at use. In computation, client-server clients request a product from the cloud. The operating system runs the test, then returns it.
  • Cloud computing is a sort of system in which the IT-related services are leased to the clients as a contract.

<u>Pros and cons of Cloud Computing:- </u>

The Pros:-

  • Lower costs for business:-The cloud is saving a lot of money for a medium-sized or small enterprise.
  • Better Reliability:- A dedicated group of experts performs all programming with such a cloud computing alternative.

The Cons:-

  • Limited Control:- When a firm stores cloud data, they have very limited control of it.
  • There have been security issues. The cloud isn't too attuned for every company to position some information on even a cloud.

<u>Pros and cons of client-server computing:- </u>

The Pros:-

  • Improved data sharing:- Data stored via the normal business method and processed on a server is available over an approved connection for the intended users.
  • Security:- Database has stronger access control and methods to ensure data could only be accessed or abused by approved clients.

The Cons:-

  • Overloaded Servers:- When multiple simultaneous requests from the client are made, the server is significantly overloaded, causing congestion in traffic.
  • Impact of centralized architecture:- Because it is centralized if a vital server fails to satisfy customer requests, the client-server then lacks good network robustness.

5 0
4 years ago
What kind of keybord is tis ned help pleese I don't no wat itis​
Murrr4er [49]

Answer:

judging by the logo at the top it's a hyperx keyboard and looks to be the alloy core rgb... hope this helps!

8 0
3 years ago
Read 2 more answers
Identify the programmer’s responsibility in maximizing the programs reliability by
Gekata [30.6K]

Software has to be reliable so that it does not create conflict or negative feelings amongst those who use it.

In this world where humans increasingly rely on the internet and software for information, programmers have to take special care so as to ensure that the members of the society are not affected negatively.

For instance, there have been moments when software led to negative effects such as:

  • when Goøgle's algorithm tagged a black couple as gorillas
  • Facebøok's algorithm tagged black men as gorillas
  • Goøgle maps gave people the wrong directions

These are but a few instances where algorithms have messed up.

We can therefore conclude that it is important that programmers take extra care when designing programs so that they do not lead to negative feelings.

<em>Find out more at brainly.com/question/21328677.</em>

6 0
3 years ago
Which of the following is NOT a Creative Commons license?
iogann1982 [59]
Commercial use is not a creative commons license
6 0
3 years ago
Write a function called factor that determines for a pair of integers whether the second integer is a factor of the first. The f
Aleks04 [339]
<h2>Answer:</h2>

//import the Scanner class to allow for user's input

import java.util.Scanner;

//Declare the class and call it FactorClass

public class FactorClass {

   

   //Declare the function factor

   //It returns either true or false, therefore the return type is boolean

   //It receives two arguments - a and b

   public static boolean factor(int a, int b){

       

       //Check if a is divisible by b.

       //Return true if yes

       if(a % b == 0){

           return true;

       }

       

       //return false if a is not divisible by b

       return false;

   

   }  // End of method factor

   

   

   //The main method to test the function factor()

   public static void main(String[] args) {

       

       //Create an object of the Scanner class

       Scanner input = new Scanner(System.in);

       

       //Prompt the user to enter the pair of numbers

       System.out.println("Enter the pair of numbers (separated by a space)");

       

       //grab and store the first number in a variable

       int firstnum = input.nextInt();

       

       //grab and store the second number in another variable

       int secondnum = input.nextInt();

       

       

       //With the variables, call the factor() method

       //If it returns true, print the adequate message

       if(factor(firstnum, secondnum)){

           System.out.println(secondnum + " is a factor of " + firstnum);

       }

       

       //If it returns false, print the adequate message

       else{

           System.out.println(secondnum + " is NOT a factor of " + firstnum);

       }

   

 }            // End of main method

   

}    // End of class declaration

==============================================================

<h2>Sample Output 1:</h2>

>> Enter the pair of numbers  separated by a space

8 4

>> 4 is a factor of 8

==============================================================

<h2>Sample Output 2:</h2>

>> Enter the pair of numbers  separated by a space

9 4

>> 4 is NOT a factor of 9

==============================================================

<h2>Explanation:</h2>

The above code has been written in Java and it contains comments explaining every segment of the code. Kindly go through the comments for better understanding of the code.

For simplicity, the code is re-written as follows with little or no comments;

import java.util.Scanner;

//Declare the class and call it FactorClass

public class FactorClass {

   

   public static boolean factor(int a, int b) {

       if(a % b == 0){

           return true;

       }

       

       //return false if a is not divisible by b

       return false;

   

   }  // End of method factor

   

   

   //The main method to test the function factor()

   public static void main(String[] args) {

       

       //Create an object of the Scanner class

       Scanner input = new Scanner(System.in);

       

       //Prompt the user to enter the pair of numbers

       System.out.println("Enter the pair of numbers (separated by a space)");

       

       //grab and store the first number in a variable

       int firstnum = input.nextInt();

       

       //grab and store the second number in another variable

       int secondnum = input.nextInt();

       

       

       if(factor(firstnum, secondnum)){

           System.out.println(secondnum + " is a factor of " + firstnum);

       }

       

       else{

           System.out.println(secondnum + " is NOT a factor of " + firstnum);

       }

    }

   

}

3 0
3 years ago
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