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d1i1m1o1n [39]
3 years ago
8

What number of cakes sold is an outlier?

Mathematics
2 answers:
user100 [1]3 years ago
7 0

Answer:

9

Step-by-step explanation:

an outlier is an observation point that is distant from other observations

nasty-shy [4]3 years ago
3 0

9, it’s further from the common area of plots

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On each round, Ann and Bob each simultaneously toss a fair coin. Let Xn be the number of heads tossed in the 2n flips which occu
CaHeK987 [17]

Answer:

P=\frac{2n!}{m!*(2n-m)!}*0.5^{2n}

Step-by-step explanation:

In a coin toss the  probability of tossing a head is 0.5 (50% head/50% tails)

If n is the number of rounds and 2n the number of coins tossed (one for each player), the probability of having m heads tossed is:

R=\frac{2n!}{m!*(2n-m)!}

R is the number of cases (combination of coins tossed) that gives a m number of heads. Each case has a probability of P_{case}=0.5^{2n} so:

P=\frac{2n!}{m!*(2n-m)!}*0.5^{2n}

<u>For example, to toss 4 heads in 5 rounds: </u>

  • n=5
  • 2n=10
  • m=4

P=\frac{10!}{4!*(10-4)!}*0.5^{10}

P=\frac{10*9*8*7*6!}{4!*6!}*0.5^{10}

P=\frac{10*9*8*7}{4!}*0.5^{10}

P=\frac{10*9*8*7}{4!}*0.5^{10}=0.205

8 0
3 years ago
HELP PLEASE
Maurinko [17]
\bf \cfrac{x^2-x-42}{x-6}\implies \cfrac{(x+7)\underline{(x-6)}}{\underline{x-6}}\implies x+7

so.. the left-hand-side does indeed simplify to x+7, so the equation does check out.

however, notice something, for the equation of x+7, when x = 6, we get (6) + 7 which is 13.

BUT for the rational, we get    \bf \cfrac{x^2-x-42}{x-6}\qquad \boxed{x=6}\implies \cfrac{x^2-x-42}{\boxed{6}-6}\implies \stackrel{und efined}{\cfrac{x^2-x-42}{0}}

so, even though the siimplification is correct, the rational or original expression is constrained in its domain.
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3 years ago
What is 20% of 80?
Gala2k [10]

Answer:

55

Step-by-step explanation:

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3 years ago
All the ways to multiply to get 65
aniked [119]

Answer:

1*65  

5*13

that is all answers one through twelve

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Can u answer this please?​
denpristay [2]
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