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3 years ago

What are the factors of 21

Mathematics

1 answer:

sweet-ann [11.9K]3 years ago

6 0

1,3,7, and 21.
:D :D :D :D :D

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Simplify the exponential expression. (−8) 2 =

sweet-ann [11.9K]

Answer:

-16

Step-by-step explanation:

6 0

3 years ago

Suzannes school are painting a rectangular mural outside the buillding that will be 15 feet by 45 feet the students are also goi

tatuchka [14]

Answer:

THE LENGTH OF THE STUDENTS PAINTING=15/3=5

THE BREADTH OF THE STUDENTS PAINTING=45/3=15

AREA OF THEIR PAINTING=15×5=75

4 0

3 years ago

Sarah lives 3 9/10 miles from school. Her classmate, Roger, lives 1 mile from school. How much farther from school does Sarah li

Veseljchak [2.6K]

Answer:

2 9/10

Step-by-step explanation:

subtract the 1 mile from the 3 9/10 mile. kinda like 3-1 but then you put the other stuff on the end (9/10)

I'm pretty sure this is the correct answer

7 0

2 years ago

Answer it quickly pls you can have all my points

Dominik [7]

Answer:

4. 55 (or is that a 56 its a low res image srry)

5. PWA is vertical, nothing is corresponding

6. 8y

7. wap is vertical 9x-2 is corresponding

8. wap is supplementary uyi is corresponding

9. tad

10. rps

5 0

1 year ago

Assume that women's heights are normally distributed with a mean given by mu equals 62.5 in, and a standard deviation given by

kirza4 [7]

Answer: a) The probability is approximately = 0.5793

b) The probability is approximately=0.8810

Step-by-step explanation:

Given : Mean : $\mu= 62.5\text{ in}$

Standard deviation : $\sigma = \text{2.5 in}$

a) The formula for z -score :

$z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

Sample size = 1

For x= 63 in. ,

$z=\dfrac{63-62.5}{\dfrac{2.5}{\sqrt{1}}}=0.2$

The p-value = $P(z$

$0.5792597\approx0.5793$

Thus, the probability is approximately = 0.5793

b) Sample size = 35

For x= 63 ,

$z=\dfrac{63-62.5}{\dfrac{2.5}{\sqrt{35}}}\approx1.18$

The p-value = $P(z$

$= 0.8809999\approx0.8810$

Thus , the probability is approximately=0.8810.

6 0

3 years ago