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asambeis [7]
3 years ago
10

Twice a number is 60 more than 5 times the number. What is the number?

Mathematics
2 answers:
IgorLugansk [536]3 years ago
8 0
Let n represent the number.

The equation would be: 
2n = 5n + 60 

Subtract 5n from both sides. 
-3n = 60
n = -20

The number is -20.
yuradex [85]3 years ago
5 0
You can put this problem into an equation:

2x=60+5x
Step 1: Subtract 5x form both sides.
-3x=60
Step 2: Divide -3 by both sides.
x=-20

Let's check our work:
2(-20)=60+5(-20)
-40=-40
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Help&amp;EXPLAIN <br> •••••••••••••••••••<br> Help plz
Stolb23 [73]

Answer:

diameter = 2.5 feet

Step-by-step explanation:

Circumference of a circle is given as C = πd

Circumference of the tree trunk = 7.85 ft

π = 3.14

Diameter of the tree trunk = d

Thus:

7.85 = 3.14*d

Divide both sides by 3.14

7.85/3.14 = 3.14*d/3.14

2.5 = d

d = 2.5 ft

3 0
2 years ago
Please help!!! 25 points or I’ll mark brainliest!!
iogann1982 [59]

Answer:

The origin is (0, 0) so let's say we have (0, 5) we find that this point is 5 units away from the origin. We find that by subtracting the origin's y coordinate from our (0, 5) point's y coordinate. This method can be used for the x-axis too.

4 0
3 years ago
What is the interquartile range (IQR) of the following data set?
OleMash [197]

Answer:

9

Step-by-step explanation:

Arrange data set

19, 4, 17, 3, 6, 5,5, 3, 11, 12, 3, 7, 15, 8, 8, 10,5, 3, 12, 41, 36

in ascending order

3, 3, 3, 3, <u>4, 5,</u> 5, 5, 6, 7, 8, 8, 10, 11, 12, <u>12, 15,</u> 17, 19, 36, 41

The median is Q_2=8

Q_1=\dfrac{4+5}{2}=4.5  

Q_3=\dfrac{12+15}{2}=13.5

Thus, the interquartile range is

Q_3-Q_1=13.5-4.5=9

4 0
3 years ago
Filip is inviting 6 friends to a party. Each friend wants 5 cookies and each box has 8 cookies. How many boxes should Filip get?
Alecsey [184]
Flip should get 4 boxes.

6*5=30
30/8=3.75
round up for 4.
3 0
1 year ago
Tripp and Rico are two dogs. Tripp weighs exactly 35 pounds more than Rico. Together, they weigh exactly 49 pounds. How much doe
babymother [125]
Call the weights of the two dogs t and r.

We know that Tripp weights 35lbs more than Rico, or:
t=r+35

We also know that the total weight of both dogs is 49lbs.:
t+r=49

Now, by substitution:
(r+35)+r=49
2r+35=49
2r+35-35=49-35
2r=14
r=\frac{14}{2}
r=7
Rico weighs 7lbs.

Then:
t=r+35
t=7+35
t=42
Tripp weighs 42lbs.

To check our work:
t+r=49
42+7=49
49=49  CHECK!
5 0
3 years ago
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