Answer: If you see my picture and you will see my answer
Step-by-step explanation: Hope this help
First you need to get a common denominator. The first two problems already have a common denominator, so you just have to find the sum and difference of the two problems, respectively.
6.) (9y-3)/(y^2-5)
8.) 3/xy^3
Two find a common denominator, find the smallest value that has BOTH denominators as factors.
10.) 8x^3*y^3 is the common denominator
Answer: 2/(8*x^3*y^3)
12.) Factor x^2 + 4x + 4 to get (x+2)(x+2)
Therefore, x+2 is already part of x^2 + 4x + 4
(x+4)/(x^2+4x+4)
14.) Factor both denominators..
4(y+2) and y(y+2)
So the common denominator would be 4y(y+2)
The first fraction is missing a "y" so multiply the numerator by y to get y^2
The second fraction is missing a "4" so multiply the numerator by 4 to get 4
(y^2 - 4)/(4y(y+2))
So can factor the numerator to get (y+2)(y-2). There if a (y+2) on top and bottom so they cancel out.
Answer: (y-2)/4y
X is greater than or equal to -6
Answer:
<u><em>FALSE</em></u>
Step-by-step explanation:
Because 15/33 is 0.454545454545...
& 22/46 is 0.47826086956
which, obviously, are not the same - or equal.
<em>MARK BRAINLIEST!</em>
x=0 .
−2(8+8x)+7x=−7x+2(x−8)
Step 1: Simplify both sides of the equation.
−2(8+8x)+7x=−7x+2(x−8)
(−2)(8)+(−2)(8x)+7x=−7x+(2)(x)+(2)(−8)(Distribute)
−16+−16x+7x=−7x+2x+−16
(−16x+7x)+(−16)=(−7x+2x)+(−16)(Combine Like Terms)
−9x+−16=−5x+−16
−9x−16=−5x−16
Step 2: Add 5x to both sides.
−9x−16+5x=−5x−16+5x
−4x−16=−16
Step 3: Add 16 to both sides.
−4x−16+16=−16+16
−4x=0
Step 4: Divide both sides by -4.
−4x
/−4
=
0
/−4
x=0
