Artificial turf on athletic fields was first introduced in the 1960’s. It’s safety has been controversial since then. One issue
that has been investigated is wether injuries of football players tend to be more serious on artificial turf instead of grass. A study followed 24 NCAA division 1A college teams over 3 seasons.
In total, there were 1,050 injuries that occurred on field turf. Of the field turf injuries, 83.3333% were minor, and 10.857% were substantial. 77.972% of grass injuries were minor. 4.26% of injuries occurred on grass and were severe. How many injuries were severe and occurred on field turf? How many injuries were severe?
In total, there were 1,050 injuries that occurred on field turf. Of the field turf injuries, 83.3333% were minor, and 10.857% were substantial. 77.972% of grass injuries were minor. 4.26% of injuries occurred on grass and were severe. How many injuries were severe and occurred on field turf? How many injuries were severe?
2 answers:
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Answer:
Step-by-step explanation:
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*Note: We do not divide by because in this case, order matters. A different order of the same four books still produces different arrangements, so the order matters.
Answer:
The maximum possible area of the pasture is 26,450 feet square.
Step-by-step explanation:
Let us assume the width of the rectangular area = m ft
and the length of the area = k ft
Also assume: ( one side with k units IS NOT FENCED)
So, the total perimeter of the fencing is:
2 m + k = 460
or, k = 460 - 2m ........ (1)
Now, AREA OF THE RECTANGULAR PORTION = Length x Width = k x m
Put k = 460 - 2m
We get: A = m (460 - 2m)
or, A = 460 m - 2m²
We need to find the maximum for the parabolic function A = 460 m - 2m²
The function has a maximum value as the quotient in front of x^2 is negative: -2 < 0
A (max) = where a = -2, b = 460, c = 0
=
A max = 26,450 sq ft.
The maximum possible area of the pasture is 26,450 feet square.