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Volgvan
2 years ago
5

Which polynomial is a perfect square trinomial?

Mathematics
1 answer:
Zigmanuir [339]2 years ago
8 0
A polynomial is a perfect square trinomial if in form

a^2x^2-2ab+b^2

look at each

we can eliminate A and B since we have -b^2 not +b^2

look at the rest

C. 5^2b-3*5*b+3^2
nope

D. 4^2x^2-2*4*3x+3^3
yes

answe is D (factors to (4x-9)^2)

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Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

120/6.4=20

It will take her 20 days

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Step-by-step explanation:

2x/3 - x/3 = x/3

they both have the same denominators (number at the bottom of the fraction) so all you have to do it subtract the numerators (top of the fraction) together. 2x-x =x, that's why it's x on the numerator for the answer

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I need help on 9 10 11 12 and 13 say the Writing to Explain Explain how you would write 5/6 as a percent
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7 0
2 years ago
The mean percentange of a population of people eating out at least once a week is 57℅
Sidana [21]

Answer:

<u>The correct answer is B. between 56.45% and 57.55% </u>

Complete statement and question:

The mean percentage of a population of people eating out at least once a week is 57% with a standard deviation of 3.50%. Assume that a sample size of 40 people was surveyed from the population a significant number of times. In which interval will 68% of the sample means occur?

between 55.89% and 58.11%

between 56.45% and 57.55%

between 56.54% and 57.46%

between 56.07% and 57.93%

Source: brainly.com/question/1068489

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Mean percentage of a population of people eating out at least once a week  = 57%

Standard deviation = 3.5%

Sample size = 40

Confidence level = 68%

2. In which interval will 68% of the sample means occur?

For answering this question, we should find out the standard deviation of the sample, using this formula:

Standard deviation of the sample = Standard deviation of the population/√Sample size

Standard deviation of the sample = 3.5/√40

Standard deviation of the sample = 3.5/6.32

Standard deviation of the sample = 0.55

Let's recall that a confidence level of 68% means that 68% of the sample data would have a value between the mean - 1 time the standard deviation of the sample and the mean  + 1 time the standard deviation of the sample. Thus:

57 - 1 * 0.55 = 57 - 0.55 = 56.45

57 + 1  * 0.55 = 57 + 0.55 = 57.55

<u>The correct answer is B. between 56.45% and 57.55% </u>

7 0
3 years ago
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