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Lerok [7]
3 years ago
5

What is the coefficient of the c-term of the algebraic expression 14a-72r-c-34d?

Mathematics
1 answer:
nydimaria [60]3 years ago
7 0
The coefficient c-term is 1 in the problem. The coefficient is the number before the variable of said equation. Example, the coefficient of x for this problem; 4x-4y, is 4. The number BEFORE the variable, never the variable itself. It won't ever be 4x, always a number, plain number.
You might be interested in
If x and x+ 10 are a pair of adjacent angle find them ​
ikadub [295]

Answer:

85° and 95°

Step-by-step explanation:

Given that , x and x + 10 are a pair of angles .

  • If they will be pair of angles on the same line , then their sum will be 180° .

=> x + x + 10° = 180°

=> 2x = 180° -10°

=> 2x = 170°

=> x = 170°/2

=> x = 85° .

<h3><u>Hence </u><u>the </u><u>two </u><u>angles</u><u> </u><u>are </u><u>8</u><u>5</u><u>°</u><u> </u><u>and </u><u>9</u><u>5</u><u>°</u><u> </u><u>.</u></h3>
5 0
3 years ago
If f(x) = 2x + 3 for all values of x, what is the value of f(-3)?​
IrinaK [193]

Answer:

f(-3)= -3

Step-by-step explanation:

We are given the function:

f(x) = 2x+3

and asked to find f(-3). Essentially, we want to find f(x) when x is equal to -3.

Therefore, we can substitute -3 for each x in the function.

f(x)= 2x+3 at x= -3

f(-3)= 2(-3) +3

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition and Subtraction

Multiply 2 and -3.

f(-3) = (2*-3) +3

f(-3)= (-6)+3

Add -6 and 3.

f(-3)= (-6+3)

f(-3)= -3

If f(x)= 2x+3, then<em> f(-3)= -3</em>

7 0
3 years ago
What is the answer to this integers (-10)(-3)(0)
damaskus [11]
ZERO

as it is eventually multiplied by 0
4 0
4 years ago
Read 2 more answers
Please help
ASHA 777 [7]

Answer:

(-6,4)

Step-by-step explanation:

The equations are:

x^2+4y^2=100\\4y-x^2=-20

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

4y-x^2=-20\\x^2=4y+20\\-------\\x^2+4y^2=100\\4y+20+4y^2=100

Now we can solve for y:

4y+20+4y^2=100\\4y^2+4y-80=0\\y^2+y-20=0\\(y+5)(y-4)=0\\y=4,-5

So plugging in y = 4 into an equation and solving for x, we have:

x^2=4y+20\\x=+-\sqrt{4y+20} \\x=+-\sqrt{4(4)+20} \\x=+-\sqrt{36} \\x=6,-6

So y = 4 corresponds to x = 6 & x = -6

The pairs would be

(6,4) & (-6,4)

<u><em>we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.</em></u>

5 0
3 years ago
Evaluate 2^3 [(15-7)] (4 divided by 2)].
Vanyuwa [196]

2^3= 8

15-7= 8

4/2= 2

8 * 8 * 2

64 * 2

answer: 128

5 0
4 years ago
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