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galina1969 [7]
3 years ago
12

An archery target consists of a circular bull's-eye with radius x, surrounded by four rings with width y. What is the area of th

e outermost ring in terms of x and y?
Mathematics
1 answer:
amid [387]3 years ago
4 0
<span>given:
   bull's eye radius= x
 width of surrounding rings=y

   solution:
   Radius of the circle=x+4y
Area of the outermost ring=Area of the circle-Area of the penultimate ring =Ď€(x+4y)^2-Ď€(x+3y)^2
=Ď€(x^2+8xy+16y^2-x^2-9y^2-6xy)
 =Ď€(2xy+7y^2)
 hence the area of the outermost ring in terms of x and y is Ď€(2xy+7y^2).</span>
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Which reason justifies step 2 in the proof
faust18 [17]

Answer:

Step-by-step explanation:

Given: ∠N≅∠S, line l bisects TR at Q.

To prove: ΔNQT≅ΔSQR

Proof:

From  ΔNQT and ΔSQR

It is given that:

∠N≅∠S (Given)

∠NQT≅∠SQR(Vertical opposite angles)

and TQ≅QR ( Definition of segment bisector)

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Hence proved.

Statement                                                 Reason

1. ∠N≅∠S                                                    given

2. ∠NQT≅∠SQR                            Vertical angles are congruent

3.  line l bisects TR at Q.                            given

4. TQ≅QR                                      Definition of segment bisector

5. ΔNQT≅ΔSQR                           AAS theorem

Hence proved.

Thus, option D is correct.

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3 years ago
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AleksandrR [38]
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3 years ago
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21 + 13.86 = 34.86

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3 years ago
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