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velikii [3]
3 years ago
15

Identify the coefficients and constants in the expression. 2x – y + 5x

Mathematics
1 answer:
garri49 [273]3 years ago
7 0
I believe the answer is 7x-y
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The units for cubic centimeters can be written as _____. Check all that apply.
GarryVolchara [31]
The correct answers for this completion exercise are the option "B" and the option "C":
 
 B. cm³
 C. cc
 
 This means that you can write the unit of volume (or capacity) cm³ as cc. 
 
 Therefore, cm³=cc
 
 For example, you have:
 
 a) 10 cm³=10 cc
 b) 110 cc=110 cm³
 c) 1 litre (l)=1000 cm³
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7 0
3 years ago
Solid a is a right, rectangular prism, in other words is a box. The length and width are double to form solid b, but the heigth
tresset_1 [31]

Answer:

The length and width dimensions of solid 'a' are multiplied by 2 while the height remains the same to get the representative quantity in solid, b

Step-by-step explanation:

The given parameters of solid 'a' are;

The shape of solid, a = Right, rectangular prism

Let 'l' represent the length of solid 'a', let 'w' represent the width of solid 'a' and let 'h' represent the height of solid 'a'

We have;

The length of solid, l_b = 2·l

The width of solid, w_b = 2·w

The height of solid, h_b = h

Given that we have;

The length of solid, b = 2 × The length of solid, a

The width of solid, b = 2 × The width of solid, a

The height of solid, b = The height of solid, a

The dimensions of length and width of each quantity in solid 'a' will be multiplied by 2 to find the dimension of a similar quantity in solid 'b'

The change in volume from solid 'a' to solid 'b' is given as follows;

The volume of solid, 'a', Vₐ = l × w × h = l·w·h

The volume of solid, 'b', V_b = 2·l × 2·w ×h = 4·l·w·h

V_b = 4 × Vₐ

Therefore, the volume of each unit volume in solid 'a' is multiplied by 4 to get the volume of the image of the unit volume in solid 'b'

The cross sectional area of solid 'a', Aₐ = l × w

The cross sectional area of solid 'b', A_b = 2·l × 2·w = 4·l·w

A_b = 4 × Aₐ

The cross sectional area of each unit of solid 'a' is multiplied by 4 to get the image of the unit cross sectional area in solid 'b'.

Therefore;

The change in the height and width of of solid 'b' is equal to a change in twice the height and width of solid 'a' at a given height, 'h'

The relationships are;

l_b = 2·l, w_b = 2·w, h_b = h

4 0
3 years ago
Consider a square whose size varies. Let s represent the side length of the square (in cm) and let P represent the perimeter of
Katena32 [7]
Formula for the square:
P=4S

5 0
3 years ago
In the following diagram, points C, A, and B are collinear. Use complete sentences to describe the sum of CA (straight line abov
blsea [12.9K]
A is the midpoint of line CB. This means that CA + AB = CB.
3 0
3 years ago
Find the seventh term of the expansion of (4x-2y)^11
Sladkaya [172]
By the binomial theorem, which says

(a+b)^n=\displaystyle\sum_{k=0}^n\binom nka^{n-k}b^k

where \dbinom nk=\dfrac{n!}{k!(n-k)!}, the seventh term of the expansion is given when k=6. Take n=11, a=4x, and b=-2y, and we get

\dbinom{11}6(4x)^{11-6}(-2y)^6=462\cdot4^5x^5\cdot(-2)^6y^6=7569408x^5y^6

Note: it's possible that you may know the binomial theorem in the reverse direction, which says

(a+b)^n=\displaystyle\sum_{k=0}^n\dbinom nka^kb^{n-k}

in which case the answer would be -60555264 x^6 y^5.
6 0
3 years ago
Read 2 more answers
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