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velikii [3]
2 years ago
15

Identify the coefficients and constants in the expression. 2x – y + 5x

Mathematics
1 answer:
garri49 [273]2 years ago
7 0
I believe the answer is 7x-y
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F(x)= 6x-5<br><br><br> need help!
Annette [7]
<h3>       </h3><h2> F-{1} (x)= x/6 + 5/6</h2>

3 0
2 years ago
If angle bisector EG is drawn find angle EGF
Gnesinka [82]

Answer:

90°

Step-by-step explanation:

because by bisecting the angle, you are going through the centre in this triangle. Splitting to triangle in half gives two right-angled triangles :)

sorry for bad drawing

6 0
3 years ago
If you lived in great Britain and wanted to but one euro HoW how much would it cost
alexgriva [62]
*looks at question for a while* .....

OH !  

If you lived in Great Britain and you wanted to buy one Euro it would cost LESS THAN A POUND . 
6 0
3 years ago
Read 2 more answers
Multiply.
Crank
The main rules that we use here are :

i) \sqrt{a \cdot b}=  \sqrt{a} \cdot \sqrt{b} for nonnegative values a and b.

ii) \sqrt{a} \cdot  \sqrt{a} =a.


Thus, first 'decompose' the numbers in the radicals into prime factors:

4 \sqrt{3} \cdot 10 \cdot  \sqrt{2\cdot2\cdot3}\cdot  \sqrt{2\cdot 3}\cdot  \sqrt{2}..

By rule (i) we write:

4 \sqrt{3} \cdot 10 \cdot \sqrt{2}\cdot \sqrt{2}\cdot \sqrt{\cdot3}\cdot \sqrt{2} \cdot  \sqrt{3} \cdot \sqrt{2}.

We can collect these terms as follows:

40 \sqrt{3}\cdot (\sqrt{3}\cdot \sqrt{3}) \cdot (\sqrt{2}\cdot \sqrt{2}) \cdot( \sqrt{2} \cdot \sqrt{2}), and by rule (ii) we have:

40 \sqrt{3}\cdot 3 \cdot 2 \cdot2=40\cdot12\cdot \sqrt{3}=480 \sqrt{3}.


Answer: 480 \sqrt{3}.
8 0
4 years ago
3) You owe $1,842.66 on a credit card at a 14.5% APR. You pay $250.00 at the beginning of the month and put another $250.00 in a
Wittaler [7]

3. Credit Card: (1842.66 - 250) (.145/12) = $19.24

Savings: 250(0.04/12) = $0.83  

Difference = 19.24 - 0.83 = $18.41  

4. Credit Card: (1842.66 - 500) (.145/12) = $16.22

You will save $18.41 - $16.22 = $2.19 by putting all $500 toward the higher credit card rate.  

8 0
3 years ago
Read 2 more answers
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