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galina1969 [7]
3 years ago
11

Please help with question 22

Mathematics
1 answer:
DedPeter [7]3 years ago
6 0

4.99x + 50 \leqslant 200
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Determine if the following equations form a perpendicular line or not
GREYUIT [131]
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If two lines are perpendicular, then they will have slopes that are <u>negative reciprocals</u> to each other. An example of negative reciprocals are 2 and -1/2

<h2>6.</h2>

Now with line 2, I have to convert it to slope intercept form. Firstly, subtract 2x on both sides of the equation: -5y=-2x+8

Next, divide both sides by -5 and your slope-intercept form is y=\frac{2}{5}x+\frac{8}{5}

Now since 2/5 is <em>not</em> the negative reciprocal of -2/5, <u>these lines are not perpendicular.</u>

<h2>7.</h2>

It's pretty much the same process; convert to slope-intercept and determine if negative reciprocal. This time I'll brush through them:

6x-3y=15 \\-3y=-6x+15\\y=2x-5\\\\2x+4y=-12\\4y=-2x-12\\y=-\frac{1}{2}x-3

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3 years ago
Find angle A using sin-1
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A=75.63

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3 years ago
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Factor by grouping

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igomit [66]
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Luba_88 [7]

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7x+14 divided by 7

\frac{7}{7} x + \frac{14}{7} \\= 1x +2\\= x + 2

Hope this helps !

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3 years ago
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