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Marizza181 [45]
4 years ago
8

An architectural firm wants to replicate a nearby estate with some changes. The new estate will be larger than the original by a

scale factor of 1:10. A section of the roof in the original estate is constructed using 45-45-90 triangles. The hypotenuse of the triangle is 10 meters long. What will be the length of the legs of the triangle for the larger estate?
141.42 meters

70.71 meters

100.00 meters

14.14 meters
Mathematics
1 answer:
Oduvanchick [21]4 years ago
8 0

Answer:

Option B.

Step-by-step explanation:

It is given that the new estate will be larger than the original by a scale factor of 1:10.

A section of the roof in the original estate is constructed using 45-45-90 triangles. The hypotenuse of the triangle is 10 meters long.

Two angles are equal and one angle is a right angle, it means it is an isosceles right-angled triangle.

Let x be the length of the legs of the triangle for the larger estate.

The hypotenuse of larger estate = 10 × 10 = 100

Using Pythagoras triangle,

perpendicular^2+base^2=hypotenuse^2

x^2+x^2=(100)^2

2x^2=10000

Divide both sides by 2.

x^2=5000

Taking square root on both sides.

x=\sqrt{5000}

x=70.71\text{ meters}

Hence, the correct option is B.

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Answer:

(1) 330

(2) 692

(3) 110

(4) 43.25

Step-by-step explanation:

The data provided is for the dying time of four different types of paint.

One-way ANOVA can be used to determine whether all the four paints have the same drying time.

Use Excel to perform the one-way ANOVA.

Go to Data → Data Analysis → Anova: Single Factor

A dialog box will open.

Select the data.

Select "Grouping" as Columns.

Press OK.

The output is attached below.

The required values are as follows:

(1)

Sum of Squares of Treatment (Between Subjects):

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(2)

Sum of Squares of Error (Within Subjects):

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(3)

Mean Squares Treatment (Between Subjects):

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(4)

Mean Squares Error (Within Subjects):

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4 0
3 years ago
six people, including A,B, and C, form a queue in a random order (all 6! orderings are equiprobable). Consider the event "B is b
mojhsa [17]

Answer:

There is a 1.39% probability that "B is between A and C in the queue".

Step-by-step explanation:

The first step to solve this problem is find the total number of possible orderings:

The first person of the queue can be any of the six. The second, can be any but the first, so five.

So

There are 6*5*4*3*2*1 = 720 total queue orderings.

Now we find the number of queues that B is between A and C. So:

We have:

B as the second, A as the first and C as the third

B as the second, C as the first and A as the third

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B as the third, C as the second and A as the fourth

B as the fourth, A as the third and C as the fifth.

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B as the fifth, A as the fourth and C as the sixth.

B as the fifth, C as the fourth and A as the sixth.

So 8 total outcomes in which B is between A and C.

What is its probability?

P = \frac{8}{720} = 0.0111

There is a 1.11% probability that "B is between A and C in the queue".

6 0
3 years ago
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Step-by-step explanation:

Given data

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Let us find 20% of $73.28

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Step-by-step explanation:

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