The answer is B. t = I/pr
The equation of a circle is written as (x-h)^2 + (y-k)^2 = r^r
H and k are the x and y coordinates of the center of the circle and r is the radius.
You are given the diameter coordinates so find the halfway point for the center then calculate the radius
Midpoint = (x1 +x2)/2, (y1 + y2)/2
Midpoint = (7 + -1)/2, (-3 +7)/2
Midpoint = 6/2, 4/2
Midpoint = 3,2
So h = 3 and k = 2
Now find radius by finding the distance between the center point and an end point.
Distance = sqrt(41)
Equation of the circle:
(X-3)^2 + (y-2)^2 = 41
Answer:
The answer is below
Step-by-step explanation:
Plotting the following constraints using the online geogebra graphing tool:
x + 3y ≤ 9 (1)
5x + 2y ≤ 20 (2)
x≥1 and y≥2 (3)
From the graph plot, the solution to the constraint is A(1, 2), B(1, 2.67) and C(3, 2).
We need to minimize the objective function C = 5x + 3y. Therefore:
At point A(1, 2): C = 5(1) + 3(2) = 11
At point B(1, 2.67): C = 5(1) + 3(2.67) = 13
At point C(3, 2): C = 5(3) + 3(2) = 21
Therefore the minimum value of the objective function C = 5x + 3y is at point A(1, 2) which gives a minimum value of 11.
Answer:
Since the question is partial, i will assume 2 scenarios:
They need to raise 1000 income
They need to make 1000 as profit
If $1000 as income:
Each ticket costs $15, so tickets would bring them $1000 income. Fractional ticket is not possible, so rounding gives us 67 tickets as the answer.
If $1000 as profit:
Their cost of renting is $700. We know that .
So, . So, to raise $1700, we need tickets. Fractional ticket is not possible, so rounding gives us 114 tickets as the answer.
ANSWER:
If need to raise atleast $1000 as income, they need to sell 67 tickets.
If need to raise atleast $1000 as profit, they need to sell 114 tickets.
The most probable answer would be 114 tickets
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