The circumference of the outer edge of the path around the pool is 113.04 ft.
<h3>
What is the circumference?</h3>
The Circumference (or) perimeter of circle = 2πR. where, R is the radius of the circle.
Given
A circular swimming pool has a radius of 15 ft.
There is a path all the way around that pool that is three feet wide.
A circle has a radius of 15 feet.
A larger circle goes around the smaller circle that is 3 feet wide.
The radius of the outer edge of the path around the pool = Radius of circle + width of outer circle.
The radius of the outer edge of the path around the pool = 15 + 3
The radius of the outer edge of the path around the pool = 18ft
The circumference of the outer edge of the path around the pool is;
Hence, the circumference of the outer edge of the path around the pool is 113.04 ft.
To know more about circumference click the link given below.
brainly.com/question/5023328
Answer:
32 divided (10-8) divided by 2-3
Answer:
Step-by-step explanation:
another math-based concept used in cybersecurity is hexadecimal math. Rather than having only two options, as in binary math, hexadecimal math is based on the idea that you can count up to any one of 16 different options. ... Cryptography is the science of codes and encryption and is based on mathematical theory
r - radius, h - height
The diameter is twice the radius.
The answer is c. 791.3 m³.
you first use distributive property for the multiplication
[(2*4x)-(2*11)]+9=19
8x-22+9=19
Then, you need to leave the variable alone moving all the other numbers with the opposite operation (addition to substraction, substraction to addition, multiplication to division, division to multiplication)
8x=19+22-9
8x=(19+22)-9
8x=41-9
8x=32
Then as 8 and x are multiplying you pass it dividing
x=32/8
x=4
