The circumference of the outer edge of the path around the pool is 113.04 ft.
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What is the circumference?</h3>
The Circumference (or) perimeter of circle = 2πR. where, R is the radius of the circle.
Given
A circular swimming pool has a radius of 15 ft.
There is a path all the way around that pool that is three feet wide.
A circle has a radius of 15 feet.
A larger circle goes around the smaller circle that is 3 feet wide.
The radius of the outer edge of the path around the pool = Radius of circle + width of outer circle.
The radius of the outer edge of the path around the pool = 15 + 3
The radius of the outer edge of the path around the pool = 18ft
The circumference of the outer edge of the path around the pool is;

Hence, the circumference of the outer edge of the path around the pool is 113.04 ft.
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Answer:
32 divided (10-8) divided by 2-3
Answer:
Step-by-step explanation:
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r - radius, h - height
The diameter is twice the radius.

The answer is c. 791.3 m³.
you first use distributive property for the multiplication
[(2*4x)-(2*11)]+9=19
8x-22+9=19
Then, you need to leave the variable alone moving all the other numbers with the opposite operation (addition to substraction, substraction to addition, multiplication to division, division to multiplication)
8x=19+22-9
8x=(19+22)-9
8x=41-9
8x=32
Then as 8 and x are multiplying you pass it dividing
x=32/8
x=4