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nlexa [21]
3 years ago
14

Suppose that the batting averages or AVG (hits per at-bat) of all players in the AAA baseball league are normally distributed wi

th a mean of 0.2 and a standard deviation of 0.05. The middle 95% of the player will have a lower bound of:____.a. 0.19.b. 0.03.c. 0.30.d. 0.07.
Mathematics
1 answer:
bulgar [2K]3 years ago
6 0

Answer:

0.1

Step-by-step explanation:

Solving using empirical rule formula

95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

Hence, the lower bound 95% =

μ - 2σ

Mean = 0.2

Standard deviation of 0.05

= μ - 2σ

= 0.2 - 2(0.05)

= 0.2 - 0.1

= 0.1

The lower bound is 0.1

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Find the volume of the figure. Round your answer to the nearest tenth if necessary. Use 3.14 for .
sp2606 [1]

Answer:

\boxed{\rm \: Volume_{(Cylinder)}  \approx \: 307.7 \: m {}^{3}  } ( \rm \: nearest \: tenth  )

Step-by-step explanation:

Given:

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To Find:

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Solution:

Use the formulae of the volume of cylinder:

\boxed{\rm \: Volume_{(Cylinder)} = \pi{r} {}^{2} h}

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According to the question:

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Substitute the values onto the formulae in order to find out the volume:

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\rm \: Volume_{(Cylinder)} = \pi(49)(2)

\rm \: Volume_{(Cylinder)} = 98\pi

\rm \: Volume_{(Cylinder)} =  \: 98 \times 3.14

\rm \: Volume_{(Cylinder)} = 307.72  \: m {}^{3} \: (exact \: form)

\boxed{\rm \: Volume_{(Cylinder)}  \approx \: 307.7 \: m {}^{3} } \: ( \rm nearest \: tenth  )

<u>Hence,we can conclude that:</u>

The volume of the cylinder is approximately

307.7m³.

8 0
2 years ago
I want answer for this one
ehidna [41]
The answer is 40
1.6/40=.04
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2 years ago
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Romashka [77]

Answer:

so what are you needing help with i dont understand the question

Step-by-step explanation:

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\begin{gathered} P=s+3+s+3+s+3+s+3 \\ =4(s+3) \end{gathered}

5 0
11 months ago
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