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nlexa [21]
3 years ago
14

Suppose that the batting averages or AVG (hits per at-bat) of all players in the AAA baseball league are normally distributed wi

th a mean of 0.2 and a standard deviation of 0.05. The middle 95% of the player will have a lower bound of:____.a. 0.19.b. 0.03.c. 0.30.d. 0.07.
Mathematics
1 answer:
bulgar [2K]3 years ago
6 0

Answer:

0.1

Step-by-step explanation:

Solving using empirical rule formula

95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

Hence, the lower bound 95% =

μ - 2σ

Mean = 0.2

Standard deviation of 0.05

= μ - 2σ

= 0.2 - 2(0.05)

= 0.2 - 0.1

= 0.1

The lower bound is 0.1

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Step-by-step explanation:

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2 years ago
Please help! (I'll give brainliest to the first right answer)
Zanzabum

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Step-by-step explanation:

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2 years ago
Which equation represents the standard form of the equation y= (x + 3)² - 4?
lilavasa [31]

Answer:

The answer is B. y = x^2 + 6x + 5

Step-by-step explanation:

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2 years ago
Hey how do you get from standard form to vertex form?
vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be \mathbf{ax^{2}+bx+c=0} where x is the variable.

Completing the square method is as follows:

  1. send the constant term to other side of equal                 \mathbf{ax^{2}+bx=-c}
  2. divide the whole equation be coefficient of \mathbf{x^{2}}, this will give     \mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}
  3. add \mathbf{(\frac{b}{2a})^{2}} to both side of equality                                   \mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}
  4. Make one fraction on the right side and compress the expression on the left side                                                                          \mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}
  5. rearrange the terms will give the vertex form of standard quadratic equation                                                                 \mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}

Follow the above procedure will give the vertex form.

(NOTE : you must know that \mathbf{(x+a)^{2}=x^{2}+2ax+a^{2}}. Use this equation in transforming the equation from step 3 to step 4)

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