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3 years ago

What is the explicit rule for this geometric sequence? 4,45,425,4125,…

2 answers:

4 0

You did not write the question correctly but I will try to answer the question according to 2 possible interpretations of your question.

Case 1:

Given the geometric sequence:

$4,\ \frac{4}{5} ,\ \frac{4}{25} ,\ \frac{4}{125} ,\ .\ .\ .$

Common ratio is given by $r= \frac{2nd\ term}{1st\ term} = \frac{ \frac{4}{5} }{4} = \frac{1}{5}$

The explicit rule of a geometric sequence is given by $T_n=ar^{n-1}$

Therefore, the explicit rule of the given sequence is $T_n=4\left( \frac{1}{5} \right)^{n-1}\ or\ 20\left( \frac{1}{5} \right)^n$

Case 2:

Given the geometric sequence:

$4,\ 4\cdot5,\ 4\cdot25,\ 4\cdot125,\ .\ .\ .$

Common ratio is given by $r= \frac{2nd\ term}{1st\ term} = \frac{4\cdot5}{4} = 5$

The explicit rule of a geometric sequence is given by $T_n=ar^{n-1}$

Therefore, the explicit rule of the given sequence is $T_n=4(5)^{n-1}\ or\ \frac{4}{5}(5)^n$

zysi [14]3 years ago

4 0

Answer:

The Answer Is An=4⋅(1/5)n−1

Step-by-step explanation:

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Someone please help me quickly i will give brainlyist

scZoUnD [109]

(16,5) it should be

16 input

5 output

if you went to 5 ont he y-axis and keep going till it hits the line the x seems to be 16.

im deeply sorry if this is wrong.

4 0

3 years ago

a mixture of peanuts and corn sells for P40 per kilo. The peanuts sell for P42 per kilo while the corn sells for P36 per kilo. h

Lelu [443]

Answer:

The weight of peanuts in the mixture = 8 kg

The weight of corns in the given mixture = 4 kg

Step-by-step explanation:

Let us assume the weight of peanuts in the mixture = x kg

The weight if corns in the given mixture = y kg

Total weight = (x + y) kg

The combined mixture weight = 12 kg

⇒ x + y = 12 ..... (1)

Cost of per kg if mixture = $ 40

So, the cost of (x + y) kg mixture = (x+y) 40 = 40(x+ y) ..... (2)

The cost of 1 kg of peanuts = $ 42

So cost of x kg of peanuts = 42 (x) = 42 x

The cost of 1 kg of corns = $ 36

So cost of y kg of corns = 36 (y) = 36 y

So, the total cost of x kg peanuts + y kg corns = 42 x + 36 y .... (3)

From (1) and (2), we get:

40(x+ y) = 42 x + 36 y

x + y = 12 ⇒ y = 12 -x

Put this in 40(x+ y) = 42 x + 36 y

We get:

40(x+ 12 -x) = 42 x + 36 (12 -x)

480 = 42 x + 432 - 36 x

or, 480 - 432 = 6 x

or, x = 8

⇒ y = 12 -x = 12 - 8 = 4

⇒ y = 4

Hence, the weight of peanuts in the mixture = 8 kg

The weight of corns in the given mixture = 4 kg

5 0

3 years ago

2 1 X 46 7. Find the m 2 JKL in rhombus JKLM

almond37 [142]

Step-by-step explanation:

since KLJ is a parallelogram, it can be split into 2 congruent triangles, as seen above. The angles remain the same, so we know angle KJL is also 25 degrees. Using the triangle angle sum theorem (all sides of a triangle add up to 180 degrees), we can determine the missing angle measure is 25 degrees. It would have been nice if the question told us JKLM was also a rhombus.

7 0

3 years ago

Seema is travelling to Guernsey. She travels a distance of 3,800 km by plane to London and then another 400 km to Guernsey. Both

slava [35]

9514 1404 393

Answer:

4 hours 40 minutes

Step-by-step explanation:

The appropriate relation is ...

time = distance/speed

time = (3800 km)/(900 km/h) +(400 km)/(900 km/h) = (38+4)/9 h

= 14/3 h = 4 2/3 h

Seema's flight time is 4 hours 40 minutes.

2/3 of 60 minutes is 40 minutes

4 0

2 years ago

In a specific video game scenario, you are given 1,000 gold. You can either train marines to defend your base at 50 gold a piece

Sloan [31]

Answer:

The system is:

$50m+200u\leq 1,000$

$u\leq 3$

$u\geq 0$

$m\geq 10$

Step-by-step explanation:

The variables of your equations are:

$m=\text{number of marines}$

$u=\text{number of upgrades}$

The constraints, which become inequalities are:

1. The total cost cannot be greater than 1,000 gold

Cost of training m number of marines at 50 gold a piece:

$50m$

Cost of purchasing u number of research weapon upgrades at 200 gold per upgrade:

$200u$

Total cost:

$50m+200u$

The cost is limited to 1,000 gold that you are given:

$50m+200u\leq 1,000$

That is the first inequality of your system

2. The game allows a maximum of three upgrades:

This sets an upper bound for the variable:

$u\leq 3$

Add the reasonable constraint that the number of upgrades cannot no be negative:

$u\geq 0$

3. You know that you need at least ten marines trained to survive

This sets a lower bound for the variable:

$m\geq 10$

And those are all the four inequalities that form your system to describe the number of marines and the number of upgrades you can train/purchae in the game:

$50m+200u\leq 1,000$

$u\leq 3$

$u\geq 0$

$m\geq 10$

3 0

3 years ago