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grin007 [14]
3 years ago
14

What is the explicit rule for this geometric sequence? 4,45,425,4125,…

Mathematics
2 answers:
gregori [183]3 years ago
4 0
You did not write the question correctly but I will try to answer the question according to 2 possible interpretations of your question.

Case 1:

Given the geometric sequence:

4,\  \frac{4}{5} ,\  \frac{4}{25} ,\  \frac{4}{125} ,\ .\ .\ .

Common ratio is given by r= \frac{2nd\ term}{1st\ term} = \frac{ \frac{4}{5} }{4} = \frac{1}{5}

The explicit rule of a geometric sequence is given by T_n=ar^{n-1}

Therefore, the explicit rule of the given sequence is T_n=4\left( \frac{1}{5} \right)^{n-1}\ or\ 20\left( \frac{1}{5} \right)^n


Case 2:

Given the geometric sequence:

4,\ 4\cdot5,\ 4\cdot25,\ 4\cdot125,\ .\ .\ .

Common ratio is given by r= \frac{2nd\ term}{1st\ term} = \frac{4\cdot5}{4} = 5

The explicit rule of a geometric sequence is given by T_n=ar^{n-1}

Therefore, the explicit rule of the given sequence is T_n=4(5)^{n-1}\ or\ \frac{4}{5}(5)^n
zysi [14]3 years ago
4 0

Answer:

The Answer Is An=4⋅(1/5)n−1

Step-by-step explanation:


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