How do I do these 2? Explain in steps please!
1 answer:
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If ΔACB is an isosceles triangle, then ∠A ≅ ∠B and AC ≅ CB
Since ∠C = 120° and ∠A + ∠B + ∠C = 180°, then ∠A = 30° and ∠B = 30°
Next, look at ΔADB. ∠A + ∠D + ∠B = 180°, so ∠A + 90° + 30° = 180° ⇒ ∠A = 30°
Now look at ΔADC. Since ∠A = 30° in ΔACB, and ∠A = 60° in ΔADB, then ∠A = 30° in ΔADC <em>per angle addition postulate.</em>
Now that we have shown that ΔADB and ΔADC are 30-60-90 triangles, we can use that formula to calculate the side lengths.
CD = 4 cm (given) so AC = 2(4 cm) = 8 cm
Since AC ≅ BC, then BC = 8 cm. Therefore, BD = 4 + 8 = 12 <em>by segment addition postulate.</em>
Lastly, look at ΔBHD. Since ∠B = 30° and ∠H = 90°, then ∠D = 60°. So, ΔBHD is also a 30-60-90 triangle.
BD = 12 cm, so HD = = 6 cm
Answer: 6 cm
Answer:
n = 17
Step-by-step explanation:
n · 170 = 34 · 85
170y = 2890
170y ÷ 170 = 2890 ÷ 170
y = 17
Answer:
See the figure attached
Step-by-step explanation:
Let's call :
x: positive response
y: negative response
then the score is:
2x - 3y
A career placement test eliminates a profession when a person receives a score of 18 or less, that's represented by the following inequality:
2x - 3y ≤ 18
