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3 years ago

1.) A. Graph A

Mathematics

2 answers:

vodka [1.7K]3 years ago

6 0

Answers:

1) To emphasize the slow increase in profits, it would be best for Bradley to use Graph A for his presentation.

2) Bradley should use this graph for his presentation becauase the profit appears to increase less on this graph.

bija089 [108]3 years ago

6 0

Answer:

ITS CORRECT!

Step-by-step explanation:

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The sum of 2 3/5 + (-1/5) write in simplest form

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The answer is 2 2/5. Need an explanation

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3 years ago

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20.Solve the triangle: b = 100, c = 100, y = 70". If it is not possible, say so.This triangle is not solvable.Q = 40", a = 68.4,

saveliy_v [14]

Answer:

$\begin{gathered} \alpha=\text{ 40\degree} \\ \beta=\text{ 70\degree} \\ a=68.4 \end{gathered}$

Step-by-step explanation:

By the theorem of intern angles of a triangle, we know that the sum of all intern angles of a triangle must be 180°, therefore:

*There are two equal angles because there are two equal sides

$\begin{gathered} \alpha=180-70-70 \\ \alpha=\text{ 40\degree} \\ \beta=\text{ 70\degree} \end{gathered}$

Now, applying the law of sines, we can find side a. The law of sines is represented by the following equation:

$\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}$

Hence, if b=100, alpha=40° and betha=70°, solve for a:

$\begin{gathered} \frac{a}{\sin (40)}=\frac{100}{\sin (70)} \\ a=\frac{100\cdot\sin (40)}{\sin (70)} \\ a=\text{ 68.4} \end{gathered}$

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1 year ago

Jasmine wants to use her savings of $1128 to buy video games and music CDs. The total price of the music CDs she bought was $72.

SashulF [63]

She can buy 24 video games max

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3 years ago

How do you convert 6.5 pounds to a fraction

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6.5 lbs/100lbs but what is it out of? 6.5 lbs out of what? 6.5/10 6.5/10000000lbs???

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3 years ago

A student wants to survey the sophomore class of 200 students about whether the school should require uniforms. A

Fittoniya [83]

Answer: C

Step-by-step explanation:

Given:

Sample size (n) = 50

x = 12

$\widehat{\mathbf{p}}=\frac{\mathbf{x}}{n}=\frac{12}{50}=0.24$

Confidence level = 90%

α = 1 − 0.90 = 0.10

α/2 = 0.05

$\text { Critical value }\left(z_{c}\right)=z_{\frac{\alpha}{2}}=z_{0.05}=1.6449$

(from standard normal table)

90% Confidence interval is,

$\begin{aligned}&\text { Confidence interval }=\widehat{\mathbf{p}} \pm z_{c} \times \sqrt{\frac{\hat{\mathbf{p}}(1-\hat{\mathbf{p}})}{n}} \\&\text { C. I }=0.24 \pm 1.6449 \times \sqrt{\frac{0.24(1-0.24)}{50}} \\&\text { C. I }=0.24 \pm 1.65 \times \sqrt{\frac{0.24(1-0.24)}{50}}\left\end{aligned}$

Therefore, 90% confidence interval for the true proportion of sophomores who favour the adoption of uniforms is C

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3 years ago