The base would represent the side adjacent to the angle and the height up the wall would be the opposite side. Using the tangent^-1 (opposite over adjacent) function we are looking for the tan^-1 of 6/24 or 14.04°
First isolate the group with h in it
minus 2pir^2 from both sides
s-2pir^2=2pirh
divide both sides by 2pir
(s-2pir^2)/(2pir)=h
we have
Group terms that contain the same variable, and move the constant to the opposite side of the equation
Factor the leading coefficient
Complete the square. Remember to balance the equation by adding the same constants to each side
Rewrite as perfect squares
-----> equation in vertex form
therefore
the answer is the option C
Answer:
C
Step-by-step explanation:
Answer:
A. Yes
Step-by-step explanation:
I calculated it logically
