The temperatures can be plotted and labelled on a number line as shown in the image attached below (see attachment).
Temperature can be represented on a vertical number line with 0 representing 0°F.
Temperatures above 0°F will be located above 0, while temperatures below 0°F will be located below 0.
Given the following temperatures: <em>-3.5℉
, 5℉, 1.5℉, -0.5℉, -2℉, 2.5℉ and -4℉</em>
Therefore, the temperatures can be plotted and labelled on a number line as shown in the image attached below (see attachment).
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Answer:
x=15
Step-by-step explanation:
divide 12/20 by 4 to get 3/5 then multiply by 3 to get your value of x
the radius of the distance between the middle point of the circle and the outside, we have the diameter which is 6 so the <u>radius will be 3</u>
slant height is

h is 4.7 and r is 3

<u>slant height is 5.58427</u>
lateral surface area


<u>lateral surface area is 52.63053</u>
total surface area



<u>total surface area is 80.90486</u>
Looking at the angles of the triangles
N=S
M=R
O=T
so MON would be RTS
Answer:
The correct option is;
DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC)
Step-by-step explanation:
Given that we have;
1) The side AD of the angle m∠ADE corresponds to the side AB of the angle m∠ABC
2) The side DE of the angle m∠ADE corresponds to the side BC of the angle m∠ABC
3) The side AE of the angle m∠ADE corresponds to the side AC of the angle m∠ABC
Then when we have DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC), we have by sin rule;
AE/(sin(m∠ADE)) = 2·(AC)/(sin(m∠ABC)) = AE/(sin(m∠ABC))
∴ (sin(m∠ADE)) = (sin(m∠ABC))
m∠ADE) = m∠ABC).